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Firlakuza [10]
3 years ago
14

What are Free Radicals ?​

Chemistry
2 answers:
DENIUS [597]3 years ago
4 0

Answer:

an uncharged molecule (typically highly reactive and short-lived) having an unpaired valency electron.

larisa [96]3 years ago
4 0

<u>an uncharged molecule (typically highly reactive and short-lived) having an unpaired valency electron.</u>

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(a) The absorbance of mixture at 400 nm was 0.40.
laiz [17]

Answer:

0.1 g/dl

Explanation:

The standard curve is a graph that relates the absorbance at 400 nm with the concentration of haemoglobin in mg/dl. To obtain the concentration from the absorbance value, we enter in the x-axis (absorbance at 400 nm) with the value 0.40 (the line between 0.2 and 0.6), we extrapolate the line to the curve and read the correspondent value on y-axis (concentration in mg/dl): 100 mg/dl.

So, we convert the concentration from mg/dl to g/dl by dividing into 1000:

100 mg/dl x 1 g/1000 mg = 0.1 g/dl

Therefore, the concentration of haemoglobin of the patient is 0.1 g/dl.

6 0
3 years ago
List 3 scenarios for a substance being classified as a weak acid
malfutka [58]
A way to classify an acid as being weak is to determine how strongly the substance conducts electricity. If the acid or base conducts electricity strongly, it is a strong acid or base. If the acid or base conducts electricity weakly, it is a weak acid or base.
4 0
3 years ago
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What kind of reaction is sncl2(s)+tibr2(s) ---&gt; snbr2+ticl2?
Elanso [62]
Chemical replacement
5 0
3 years ago
PLEASE HELP!!! Which type of substance is gold an example of?
dmitriy555 [2]

Answer:

Hello!

Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal. Chemically, gold is a transition metal and a group 11 element.

So in short, the Correct Answer will be (D) an Element.

Hope that Helps! Have A Wonderful Day! ☺

Explanation:

7 0
2 years ago
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vekshin1

Answer:

i am potato

Explanation:

4444141+5-45458/85*55474

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