Answer & Explenation:
2H2 + O2 -> 2H20 is the balanced equation for the reaction of Hydrogen with Oxygen to form water so
If you have 32g of O2 this is a simple Dimensional analysis problem
32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced. Just a different way to view and solve the problem with the balanced equation so you can see the way everything relates to everything else. the molar masses of O2 and H2O are simply found my adding up 2 Oxygens 15.9994g x2 = 31.9988g and H2O = 2(1.00794) + 15.9994 = 18.01258 but you then have to multiply that by 2 because the reaction states you get 2 mols in the reaction so that is where I came up with the 36.03056g for the solution. Hope this helps. Dimensional Analysis is and can be one of the best ways to solve these problems, because not always are you going to be dealing with 1:2 ratios.
Answer :
<h2>
Multicellular organisms</h2>
Explanation :
Coyotes are multicellular organisms.
Trees are multicellular organisms. They are made up of eukaryotic cells, which are complex cells full of organelles.
Answer:
k = -0.0525 s⁻¹
Explanation:
The equaiton for a first order reaction is stated below:
ln[A]=−kt+ln[A]₀.
[A] = 5.50 x 10⁻³ M
[A]₀ = 7.60 x 10⁻² M
t = 85.0 - 35.0 = 50.0 s
The rate constant is represented by k and can be calculated substituting the values given above:
k = (ln[A]₀ - ln[A])/t
k = (ln5.50 x 10⁻³ M - ln7.60 x 10⁻² M)/50.0s
k = -0.0525 s⁻¹
<span>_____Balanced Chemical eqn___
C6H5OH + 7O2 --> 6C02 + 3H20
Firstly, heat of rxn will be absorbed by bobm calorimaeter, so find the qcal
qcal = CΔT
= (11.66 KJ/°C)(26.37°C- 21.36°C)
= 58.42 KJ
since the heat of rxn absorbed by calorimeter, assume:
qrnx = -qcal
= - 58.42 KJ
_____q GRAM OF C6H5OH______
Find the number of moles you have by dividing the given grams of C6H5OH by its molar mass
(1.8 g C6H5OH)(94 g/mole C6H5OH) = 0.0191 mol C6H5OH
then divide qrnx by the number of moles.
(-58.42 KJ)/(0.0191 mol C6H5OH) = -3058.64 KJ/mol C6H50H</span>
