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frutty [35]
3 years ago
9

A(n) __________ is a gravitationally curved path that a celestial body travels around a point in space. A(n) __________ is a gra

vitationally curved path that a celestial body travels around a point in space. retrograde motion small circle epicycle planet orbit
Physics
1 answer:
joja [24]3 years ago
5 0

Answer: A planet orbit is a gravitationally curved path that a celestial body travels around a point in space.

Explanation:

We define planet orbit as the path that a planet (or any other celestial object) has around two focal points (the orbit is an ellipse, the ellipses have two focal points). For example, the moon's orbit is around the Earth is almost circular, while Earth orbit is less circular. This movement is caused by the strong gravitational attraction of the sun, that keeps all the planets fixed in the orbits, this is why this is called a "gravitationally curved path".

the correct option is planet orbit.

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How much heat is released when 432 g of water cools down from 71'c to 18'c?
maria [59]
The heat released by the water when it cools down by a temperature difference \Delta T is
Q=mC_s \Delta T
where
m=432 g is the mass of the water
C_s = 4.18 J/g^{\circ}C is the specific heat capacity of water
\Delta T =71^{\circ}C-18^{\circ}C=53^{\circ} is the decrease of temperature of the water

Plugging the numbers into the equation, we find
Q=(432 g)(4.18 J/g^{\circ}C)(53^{\circ}C)=9.57 \cdot 10^4 J
and this is the amount of heat released by the water.
7 0
3 years ago
If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
pogonyaev
Let h =  distance (m) to the water surface.

Initial velocity, u  = 0 (because the stone was dropped).
Use the formula
 h = ut + (1/2)gt^2
  where g = 9.8 m/s^2  (acc. due to graity)
              t = time (s)

h = (1/2)*(9.8)*(3^2) = 44.1 m
8 0
3 years ago
Which are the three types of mutations?
WITCHER [35]
Replication, Multiplication, and Substitution.
7 0
3 years ago
Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
The distance between the two points then is equal to 7.07 m.


</span>
8 0
2 years ago
Protons have a positive charge<br><br> A.True<br> B.False
PIT_PIT [208]

Answer:

TRUE

Explanation:

Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

5 0
3 years ago
Read 2 more answers
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