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frutty [35]
3 years ago
9

A(n) __________ is a gravitationally curved path that a celestial body travels around a point in space. A(n) __________ is a gra

vitationally curved path that a celestial body travels around a point in space. retrograde motion small circle epicycle planet orbit
Physics
1 answer:
joja [24]3 years ago
5 0

Answer: A planet orbit is a gravitationally curved path that a celestial body travels around a point in space.

Explanation:

We define planet orbit as the path that a planet (or any other celestial object) has around two focal points (the orbit is an ellipse, the ellipses have two focal points). For example, the moon's orbit is around the Earth is almost circular, while Earth orbit is less circular. This movement is caused by the strong gravitational attraction of the sun, that keeps all the planets fixed in the orbits, this is why this is called a "gravitationally curved path".

the correct option is planet orbit.

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Viktor [21]

A transcript of a presidential speech (APEX Class ;)

7 0
3 years ago
A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in
miv72 [106K]

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is \mu_s =  0.60

The value for static friction is \mu_k =  0.70

Explanation:

From the question we are told that

The mass of the clock is m  =  95 \  kg

The first horizontal force is F _s  =  560 \  N

    The second horizontal force is    F _k  =  650  \  N

Generally the static frictional force is equal to the first  horizontal force

So

     F _s  =  m  *  g  *  \mu_s

=>   560  =  95  *  9.8  *  \mu_s

=>    \mu_s =  0.60

Generally the kinetic frictional force is equal to the second horizontal force

So

      F _k  =  m  *  g  *  \mu_k

      650 =  95  *  9.8  *  \mu_k

     \mu_k =  0.70

3 0
3 years ago
How i can change my bad habits and one is i always trust peopñe
Lelu [443]

what? I guess:

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this question doesn't make any sense...

5 0
3 years ago
Read 2 more answers
A projectile is fired vertically from Earth's surface with
scoray [572]

Answer:

h=25.52\times10^6 m

Explanation:

Initial speed, v = 10 x 10^3 m/s

Mass of the earth, M = 6 x 10^24 kg

Radius of the earth, R = 6.4 x 10^6 m

Maximum from the surface of earth, h = ?

Let  m = Mass of the projectile

Solution:

Potential energy at maximum height =  ( Potential + Kinetic energy ) at the surface

-G M m / ( R + h )=- G M m / R + (1/2) m v^2

- G M / ( R + h ) = - G M / R + (1/2) v^2

-2\times G M / ( R + h ) = ( - 2 G M / R ) + v^2

-2\times6.67\times10^{-11}\times6\times10^{24}/ ( R + h )

=( (- 2\times 6.67\times10^{-11}\times6\times10^{24}) /(6.4\times10^6)} +10000^2

=-2.50625\times10^7 J

=- 8\times10^{14} / ( R + h )=-2.50625\times 10^7

R+h=31.92\times10^{6}

h=31.92\times10^{6}-6.4\times10^6

h=25.52\times10^6 m

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3 years ago
There isnt enough sanitidzer(alcohol)what solution to be replaced
Alex Ar [27]

For me: WASH OUR HANDS REGULARLY

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2 years ago
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