Answer:
Explanation:
tensile strength is stress that is needed to break the wire made of the material .
Here force required to break the sheet of material = 233 N
cross sectional area of the foil = breadth x thickness
= 5 x 10⁻² x 15 x 10⁻⁶ m²
= 75 x 10⁻⁸ m²
breaking stress = force / cross sectional area
= 233 / 75 x 10⁻⁸
= 3.1 x 10⁸ Pa .
Tensile strength = 3.1 x 10⁸ Pa .
Answer:
Explanation:
We shall solve this question with the help of Ampere's circuital law.
Ampere's ,law
∫ B dl = μ₀ I , B is magnetic field at distance x from the axis within wire
we shall find magnetic field at distance x . current enclosed in the area of circle of radius x
= I x π x² / π R²
= I x² / R²
B x 2π x = μ₀ x current enclosed
B x 2π x = μ₀ x I x² / R²
B = μ₀ I x / 2π R²
Maximum magnetic B₀ field will be when x = R
B₀ = μ₀I / 2π R
Given
B = B₀ / 3
μ₀ I x / 2π R² = μ₀I / 2π R x 3
x = R / 3
b ) The largest value of magnetic field is on the surface of wire
B₀ = μ₀I / 2π R
At distance x outside , let magnetic field be B
Applying Ampere's circuital law
∫ B dl = μ₀ I
B x 2π x = μ₀ I
B = μ₀ I / 2π x
Given B = B₀ / 3
μ₀ I / 2π x = μ₀I / 2π R x 3
x = 3R .
Answer:
The final temperature is 21.531°c
Explanation:
Heat gained by the water = heat lost by the metal
Heat gained = (m)(c)(∆tita)
Where m = mass
C = specific heat capacity
∆tita = temperature change
X = equilibrium temperature
So ....
Heat gained by water
= 175*4.185*(x-20)
= 732.2x - 14644
Heat lost by metal
= 44.5*0.321*(100-x)
=1428.45 -14.2845x
So....
1428.45 - 14.2845x = 732.2x - 14644
1428.45+14644= 732.2x + 14.2845x
16072.45= 746.4845x
16072.45/746.4845= x
21.531 = x
The final temperature is 21.531°c
"The maximum extent of a vibration or oscillation"
-Quora
...
<span>use this equation </span>
<span>F delta(t) = m delta(v) </span>
<span>F (0.50) = 3.6 (3.3) </span>
<span>F = 23.8 N </span>
