Answer:
The hummingbird travels the total distance is 10 m
Explanation:
Given that,
A hummingbird flies forward and backward.
According to figure,
We know that,
The total distance is equal to the sum of all distance.
Forward direction is positive and backward direction is negative.
We need to calculate the hummingbird travels the total distance
Using figure,

Put the value into the formula


Hence, The hummingbird travels the total distance is 10 m.
Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial (
) and final speeds (
), measured in meters per second, of the aircraft and likewise the runway length (
), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (
), measured in meters per square second:

If we know that
,
and
, then the acceleration that the jet must have is:


The acceleration that the jet liner that must have is 2.241 meters per square second.