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Alika [10]
2 years ago
12

Define 1 joule work ?​

Physics
1 answer:
Nina [5.8K]2 years ago
4 0

Explanation:

Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)

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Explain what will happen if an object has high momentum or low momentum and a force is applied?
Korvikt [17]

-- If the force is applied in the <em>same direction</em> as the object is moving, then the object's momentum in that direction will <em>increase</em>.

-- If the force is applied in the direction <em>OPPOSITE </em>to the way the object is moving, then the object's momentum will <em>decrease</em>.

-- In either case, the CHANGE in the object's momentum will be

(strength of the force) x (length of time the force is applied) .

This quantity is also called "impulse".

5 0
3 years ago
What is the speed of a wave frequency of 300hz and a wavelength of 25M
tia_tia [17]

Answer:

7500 m/s

Explanation:

We can use the equation velocity of a wave equals wavelength times  frequency.  Therefore, v = wavelength*f = (25 m)(300 Hz) =  m/s7,500

8 0
3 years ago
In a football game, running back is at the 10-yard line and running up the field towards the 50 yard
kotykmax [81]

Answer:

34 yards or 34 yard line

Explanation:

8 × 3 = 24

24 + 10 = 34

8 0
3 years ago
Who is responsible for developing the three laws of planetary motion?
Ivenika [448]
Johannes Kepler- he did it by observing the ‘Tycho Brahe’. His 3rd law was published 10 years later to his first two laws.
3 0
3 years ago
2. A 3 kg ball is thrown downward at 4 m/s from a height of 1.5 m. a. What is the kinetic energy of the ball as it leaves the th
ludmilkaskok [199]

Answer:

a) 24 J

b) Gravitational Force

c) 45 J

d) 0

e) 6.782m/s

Explanation:

a) m = 3kg

v = 4m/s

h = 1.5m

KE = ?

0.5 * 3 * 16 = 24J

b) Gravitational force

c) F = ma = 3 * 10 = 30N

Work done = Force * distance = 30 * 1.5 = 45J

d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving

e) velocity of ball as it strikes the ground = v

v^{2} - u^{2} = 2as where

v is the velocity as it strikes the ground

u is the initial velocity

a is acceleration

s is the distance

Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it

u = 4m/s

a = 10

s = 1.5

=>  v = \sqrt{2as + u^{2} }

= \sqrt{(2*10*1.5) + 16}

= \sqrt{46} = 6.782m/s

3 0
3 years ago
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