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Alika [10]
2 years ago
12

Define 1 joule work ?​

Physics
1 answer:
Nina [5.8K]2 years ago
4 0

Explanation:

Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)

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Blank is the the decrease in a materail's volume when it's blank decrease ​
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Answer:

Explanation:

becAUSE IT POOOPYES

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3 years ago
Which term refers to a variable that a scientist adjusts during an experiment?
azamat

Answer:

it’s c

Explanation:

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A 0.55 kg projectile is launched from the edge of a cliff with an initial kinetic energy of 1550 J and at its highest point is 1
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Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

5 0
2 years ago
within ____minutes after a drink is consumed all of the alcoholic content has probably been absorbed into your body
OverLord2011 [107]

20-60minutes

Explanation:

Within 10-20minutes after a drink is consumed all of the alcoholic content has probably been absorbed into body.

Alcohol is absorbed into the body much more fast.

  • It does not undergo digestion process like food.
  • It can easily be absorbed into the blood stream.
  • Alcohol is readily absorbed and carried round into the body.
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3 0
3 years ago
A spring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. It is then compressed from x=0 to x=
VARVARA [1.3K]

Answer:

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

U=\frac{1}{2}k (\Delta x)^2

where

k is the spring constant

\Delta x is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

\Delta x = d-0=d

and the amount of energy required is

U=\frac{1}{2}k d^2

In the second case, the spring is compressed from x=0 to x=-d, so

\Delta x = -d -0 = -d

and the amount of energy required is

U=\frac{1}{2}k (-d)^2= \frac{1}{2}kd^2

so we see that the amount of energy required is the same.

7 0
3 years ago
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