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Karolina [17]
3 years ago
15

Some plants disperse their seeds by having the fruit split and contract, propelling the seeds through the air. The trajectory of

these seeds can be determined by using a high-speed camera. In one type of plant, seeds are projected at 20 cm above ground level with initial speeds between 2.3 m/s and 4.7 m/s . The launch angle is measured from the horizontal, with +90∘ corresponding to an initial velocity straight upward and −90∘ straight downward.
Physics
1 answer:
Pani-rosa [81]3 years ago
3 0

Answer: 23000 frames/s

Explanation:

The rest of the statement of the question is presented below:

The experiment is designed so that the seeds move no more than 0.20 mm between photographic frames. What minimum frame rate for the high-speed camera is needed to achieve this?

We know the <u>maximum initial speed</u> at which the seeds are dispersed is:

V_{i}=4,7 m/s

In addition, we know the <u>maximum distance</u> at which the seeds move between photographic frames is:

d_{max}=0.20 mm \frac{1m}{1000 m}=0.0002 m

And we need to find the minimum frame rate of the camera with these given conditions. This can be found by finding the time t for each frame and then the frame rate:

Finding the time:

t=\frac{d_{max}}{V_{i}}

t=\frac{0.0002 m}{4.6 m/s}

t=0.00004347 s/frame This  is the time for each frame

Now we need to find the frame rate, which is the frequency at which the photos are taken.

In this sense, frequency f is defined as:

f=\frac{1}{t}

f=\frac{1}{0.00004347 s/frame}

Finally:

f=23000 frames/s

Hence, the minimum frame rate is 23000 frames per second.

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a object with a mass of 70 kilograms is supported at a height 8 meters above the ground.what's the potential energy of the objec
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Potential Energy = mgh,

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Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h​
ELEN [110]

Answer:

1848.15J

Explanation:

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A bowling ball is far from uniform. Lightweight bowling balls are made of a relatively low-density core surrounded by a thin she
tester [92]

Answer:

a)  I = 1,75 10-² kg m²  and b)  I = 1.49 10⁻² kg m²

Explanation:

The expression for the moment of inertia is

    I = ∫ r² dm

The moment of inertia is a scalar by which an additive magnitude, we can add the moments of inertia of each part of the system, taking into account the axis of rotation.

    I = I core + I shell

The moment of inertia of a solid sphere is

    I sphere = 2/5 MR²

The moment of inertia of a thin spherical shell is

    I shell = 2/3 M R²

a) Let's apply to our system, first to the core of weight 1.6 kg and diameter 0.196m, the radius is half the diameter

     R = d / 2

     R= 0.196 m / 2 = 0.098 m

     I core = 2/5 1.6 0.098²

     I core = 6.147 10-3 kg m²

Let's calculate the moment of inertia of the shell of mass 1.6 kg with a diameter of 0.206 m

    R = 0.206 / 2

    R = 0.103 m

    I shell = 2/3 1.6 0.103²

    I shell = 1,132 10-2 kg m²

The moment of inertia of the ball is the sum of these moments of inertia,

    I = I core + I shell

    I = 6,147 10⁻³ + 1,132 10⁻² = 6,147 10⁻³ + 11.32 10⁻³

    I = 17.47 10⁻³ kg m²

    I = 1,747 10-² kg m²

b) Now the ball is report with mass 3.2kg and diameter 0.216 m

    R = 0.216 / 2

    R = 0.108 m

It is a uniform sphere

    I = 2/5 M R²

    I = 2/5 3.2 0.108²

    I = 1.49 10⁻² kg m²

7 0
3 years ago
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