<u>Ans: P = 22.5% and Cl = 77.5%</u>
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<u>Given:</u>
Total Mass of sample containing P and Cl = 50.51 g
Mass of P produced = 11.39 g
<u>To determine:</u>
Mass % of P and Cl
<u>Explanation:</u>
Mass % of a given element in a total mass is generally expressed as:
Mass % of element = [mass of element/total mass]*100
Here,
Total mass = mass of P + mass of Cl
mass of Cl = Total - mass of P = 50.51-11.39 = 39.12 g
% P = [11.39/50.51]*100 = 22.5%
%Cl = [39.12/50.51]*100 = 77.5%
After careful consideration your answer is...
Leucippus and Democritus
*Hope I helped*
~Alanna~
<span>389.88094 amu
First we look up the atomic mass of all elements contained in calcium iodate using the periodic table:
Ca: 40.078
I: 126.90447
O: 15.999
As an intermediate step we calculate the molecular mass of the ion IO3:
126.90447 + 3*15.999 = 174.90147
Then we calculate the mass of one calcium atom and 2 iodate ions:
2*174.90147 + 40.078 = 389.88094 amu</span>
Answer:
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Explanation: