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damaskus [11]
3 years ago
14

In which of the following is the solution concentration expressed in percent by volume

Chemistry
2 answers:
Hitman42 [59]3 years ago
8 0

Answer : The correct option is, \frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%

Explanation :

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

\text{Percent solution by volume}=\frac{\text{Amount of solute}}{\text{Amount of solution}}\times 100\%

Or,

\text{Percent solution by volume}=\frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%

Hence, the correct option is, \frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%

sleet_krkn [62]3 years ago
4 0
10ml of solute/100ml of solution *100% third one
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Thus, the highest buffer capacity is found in the solution that has the highest concentration of the conjugate acid-base pair, which is 1.25 M HCO₃⁻ / 1.25 M CO₃²⁻ .

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Put the list in chronological order (1–5).
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If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
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Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

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The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

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x = 0.36 M

The equilibrium concentration of each gas:

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3 years ago
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