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adelina 88 [10]
2 years ago
10

Please help me with these 3 questions with will be giving out brainiest

Chemistry
1 answer:
Anna71 [15]2 years ago
5 0

Answer: All of them are true

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A car can accelerate from a standstill to 100 km/h [E] in 9.60s. calculate the average acceleration
Lelu [443]

Answer:

Acceleration is :

a = 2.89 m/s2

Explanation:

Acceleration : It is the change in the velocity of the object per unit time.

The object starts from the rest , so the initial velocity of the object is zero.

Initial velocity , u = 0

Final velocity = 100 km/h

Change the velocity to m/s because[ time unit is in second(9.60 s)]

1 km = 1000 m

1 hour = 60 x 60 sec = 3600 sec

1km/h=\frac{1000}{3600}m/s

1km/hr=\frac{5}{18}

100km/hr=\frac{5}{18}\times 100

v=\frac{5}{18}\times 100

v = 27.78 m/s

u = 0 m/s

time = 9.60 s

The acceleration"a" is calculated using :

a=\frac{v-u}{t}

a=\frac{27.78-0}{9.6}

a=\frac{27.78}{9.6}

a=2.89m/s^{2}

5 0
2 years ago
CN- is a Bronsted - Lowry base. What will this substance form when it accepts a proton?
sergejj [24]
It will form HCN Hydrogen Cyanide.
8 0
2 years ago
Can someone help me with this?
dolphi86 [110]

The answer would have to be “move fast and far apart.”

I really hope this helps you.

5 0
3 years ago
Read 2 more answers
A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de
kirill115 [55]

Answer: -15.4^00C

Explanation:

T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = boiling point of solution = ?

T^o_f = boiling point of solvent (X) = -10.1^oC

k_f = freezing point constant  = 5.32^oC/kgmol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

M_2 = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}

T_f=-15.4^0C

Therefore, the freezing point of  solution is -15.4^0C

7 0
2 years ago
Na sua época quais foram as condições experimentais que Lavoisier utilizou em suas experiências ?
Olin [163]

Answer:

What are u saying

Explanation:

umm ok sorry i didnt understand anything

3 0
2 years ago
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