i. The new concentration is 0.116 M
ii. The new concentration is 0.029 M
<h3>What is the concentration of the original hydrochloric acid acid?</h3>
The concentration of the original or stock hydrochloric acid is calculated as follows:
- Molarity = Percentage concentration * Density * 1000/Molar mass * 100
Molarity of stock HCl = 36 * 1.18* 1000 /36.5 * 100
Molarity of stock HCl = 11.6 mol/dm
i. Using the dilution formula: M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 11.6 * 10/1000
M₂ = 0.116 M
The new concentration = 0.116 M
ii. Using M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 0.116 * 5/20
M₂ = 0.029 M
The new concentration = 0.029 M
In conclusion, the new concentrations are found using the dilution formula.
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Answer:
1. This reaction is <u>(A) Exothermic .</u>
2. When the temperature is decreased the equilibrium constant, K: <u>(A) Increases</u>
3.When the temperature is decreased the equilibrium concentration of Co2:<u> (A) Increases</u>
Explanation:
1. The pink color predominates at low temperatures, indicating that the commodity is preferred.
This is a reaction that is <u>exothermic.</u>
2. As the decrease in the temperature , the equilibrium constant , K ;
equilibrium constant = 
=![\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5E2%5E%2B%5D%5BCl%5E-%5E4%5D%7D%7BCoCl%5E2%5E-_4%7D)
As the temperature drops, the concentration of
and 
rises, and K rises as well , thus it <u>increases </u>.
3. The equilibrium concentration of decreases as the temperature decreases:
When the temperature is lowered, the equilibrium shifts to the right , that is it <u>increases.</u>
Answer:
15 electrones: 1S²2S²2P⁶3S²3P³. Fósforo
27 electrones: 1S²2S²2P⁶3S²3P⁶4S²3d⁷ - Cobalto.
56 electrones: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² - Bario
49 electrones: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p¹ - Indio
Explanation:
Para llenar los orbitales electrónicos de los distintos átomos debemos hacer uso de la regla de llenado electrónico de Aufbau. Por ejemplo, para el átomo con 15 electrones, la configuración electrónica es:
1S²2S²2P⁶3S²3P³. 2+2+6+2+3 = 15 electrones
Si elemento es neutro, tiene 15 protones. Es decir, es el fósforo, P.
27 electrones:
1S²2S²2P⁶3S²3P⁶4S²3d⁷ - Cobalto.
56 electrones:
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² - Bario
49 electrones:
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p¹ - Indio
Answer:
Van't Hoff factor for AlCl₃ = 3 (Approx)
Explanation:
Given:
Number of observed particular = 1.79 M
Number of theoretical particular = 0.56 M
Find:
Van't Hoff factor for AlCl₃
Computation:
Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular
Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M
Van't Hoff factor for AlCl₃ = 3.19
Van't Hoff factor for AlCl₃ = 3 (Approx)
