1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
4 years ago
14

A ray diagram is shown.

Physics
2 answers:
Svetlanka [38]4 years ago
6 0

Answer:

It is virtual and behind the mirror

Explanation:

When an image is produced by a mirror, we have the following situations:

- The image is said to be in front of the mirror if it is on the same side of the object, with respect to the mirror

- The image is said to be behind of the mirror if it is on the opposite side of the object, with respect to the mirror

Moreover:

- The image is said to be real if it is in front of the mirror

- The image is said to be virtual if it is behind the mirror

In this case, the image (located at point I) is on the opposite side of the object (located at point O), so it is virtual and behind the mirror.

Dima020 [189]4 years ago
6 0

Answer:

virtual and behind the mirror...hope this helps :))))

You might be interested in
Is a pair of sneakers a want or a need? Is the most expensive pair of sneakers a want or a need?
IgorLugansk [536]

Explanation: A sneaker is a want because you don't actually need it to survive

8 0
3 years ago
A pilot performs an evasive maneuver by diving vertically at 270. If he can withstand an acceleration of 9.0 's without blacking
mamaluj [8]

Answer:

The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

Explanation:

Given that,

Velocity = 270 m/s

Acceleration = 9.0g s

We need to calculate the altitude

Using formula of centripetal acceleration

a_{c}=\dfrac{v^2}{r}

r=\dfrac{v^2}{a_{c}}

Where, v = velocity

r = altitude

a = acceleration

Put the value into the formula

r=\dfrac{270^2}{9.0\times9.8}

r=826.53\ m

Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

6 0
3 years ago
What is the electric force on a proton 2.5 fm from the surface of the nucleus? hint: treat the spherical nucleus as a point char
Whitepunk [10]
In this case, you need the formula below where:

F = force
k = coulombs constant 8.99 x10^{9} N.m^{2} . C^{-2}
q1 = electric charge 1
q2 = electric charge 2
r = the distance between the charges

F = k((q1.q2)/r^{2})

pls note: make sure your units are correct (in meters etc, not fm (<em>femto-meters</em>)).

Curiously, this question doesn't tell you what atom you are next to the nucleus of. Different numbers of protons in the nucleus of the atom will make for vastly different forces in your answer...
6 0
3 years ago
An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2&#10;}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
3 years ago
if you're shopping for a rack switch, what component on the switch tells you it can be mounted to a rack?
Tatiana [17]

if you're shopping for a rack switch, the component on the switch that tells you it can be mounted to a rack is the:

  • Rack ears

<h3>What are rack ears?</h3>

Rack ears are L-shaped objects that can be used to hold a rack switch firmly to the support walls. Rack ears are often found at the front panel of the rack which is to be mounted.

When a person purchases a rack switch and finds the rack ears there, it is a signal that the item can be secured firmly to rails. Sometimes, the rack ears also appear as extensions.

Learn more about rack ears here:

brainly.com/question/13318148

#SPJ4

6 0
2 years ago
Other questions:
  • If during the last 100 feet of approaching a railroad crossing, you cannot see the track for at least 400 feet in both direction
    10·1 answer
  • Can you use a machine to gain both force and speed at the same time? explain.
    8·1 answer
  • Which of the following can a cell contain. A. a number B. a word C. a function D.all of these.
    8·2 answers
  • What is the slope of (0,0)(4,200)
    8·2 answers
  • Please help Need good grade
    5·1 answer
  • the weight of 80 kg of mass on mercury is 296 N and almost identical to the weight of the same mass on Mars but mercury has much
    7·1 answer
  • Joe and Max shake hands and say goodbye. Joe walks east 0.35 km to a coffee shop, and Max flags a cab and rides north 3.70 km to
    13·2 answers
  • Which of these are true for Light? (pick 3)
    6·1 answer
  • What is the potential energy of a 2 kg rock sitting at the top of a 10 meter high cliff?
    12·1 answer
  • A micro element that is essential for the formation of haemoglobin
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!