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3 years ago

How do earths movements affect our view of the star

2 answers:

7 0

In the solar system the Earth rotates around the sun and the moon rotates around the Earth. this cause half of the earth to be bright at a time.. the moon has different phases which causes the earth to be affected

Rzqust [24]3 years ago

4 0

As the Earth makes a full revolution, we see the sun and no stars, except the sun, and when our section of Earth is facing away from the sun we can see other starts.
Also, as the Earth revolves around the sun, certain stars can be seen and certain stars go out of view.

Hope this helps!!(:

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The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the

otez555 [7]

Answer:

0.647 nC

Explanation:

The force experienced by a charge due to the presence of an electric field is given by

$F=qE$

where

q is the charge

E is the magnitude of the electric field

In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

$F=5.50\mu N = 5.50\cdot 10^{-6} N$

Therefore, if the electric field magnitude is

$E=8.50 kN/C = 8500 N/C$

Then the charge on each antenna would be

$q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC$

8 0

4 years ago

A chain saw produces a spherical sound wave having a frequency of 214Hz in air at 358C (308.2K or 958F). At a distance of 600mm

Helen [10]

Given Information:

Frequency = 214 Hz

Temperature = 358° C = 308.2 K

Sound Pressure = p = 100 dB = 2 pascal

Distance = 600 mm = 0.60 m

Required Information:

(a) Acoustic Power Level = ?

(b) Acoustic Particle Velocity = ?

and Velocity level at a distance of 600 mm = ?

Answer:

Acoustic Power Level = Lw = 106.44 dB

Acoustic Particle Velocity = v = 0.0106 m/s

Velocity level = 60.25 dB

Explanation:

(a) Acoustic Power Level

Acoustic Power = W = 4πr² I

Acoustic Intensity = I = p ²/Z₀

Where Z₀ is the characteristic impedance of air Z₀ = 409.8 rayl

I = p ²/Z₀ = (2)²/409.8 = 0.00976 W/m²

W = 4πr² I = 4*π(0.60)²*0.00976 = 0.0441 W

Acoustic Power Level = Lw = 10log(W/Wref)

Where Wref is Reference Acoustic Power Wref = 1x10⁻¹² W

Lw = 10log(W/Wref) = 10log(0.0441/1x10⁻¹²) = 106.44 dB

Lw = 106.44 dB

(b) Acoustic Particle Velocity

Acoustic Particle velocity = v = p ²/Zs

Where Zs is specific acoustic impedance

Zs = Z₀kr/(1 + k²r²)⁰°⁵

Where k = 2πf/c and c = 346.1 m/s is the speed of sound in air

k = 2π*214/346.1 = 3.885 per m

Zs = 409.8*3.885*0.60/(1 + (3.885)²(0.60)²)⁰°⁵

Zs = 376.6 rayl

v = p ²/Zs = 2²/376.6 = 0.0106 m/s

v = 0.0106 m/s

Velocity level = 10log(v/vref) where vref = 10x10⁻⁹ m/s

Velocity level = 10log(0.0106/10x10⁻⁹) = 60.25 dB

Velocity level = 60.25 dB

8 0

4 years ago

A softball is thrown from the origin of an x-y coordinate system with an initial speed of 18m/s at an angle of 35 degrees above

Bond [772]

Distance = speed × time

After 0.5s , horizontal distance covered is 0.5s × 18m/s = 9m

9m/ y position = cos 35° , y position = 9 ÷ cos 35° = 10.9870m (rounded up to nearest four decimal places)

After t = 1.0s:

Horizontal distance = 18m/s × 1.0s = 18m

y position = $\frac{18m}{cos 35°}$ = 21.9740m (rounded up to nearest four decimal places)

After t = 1.5s:

Horizontal distance = 18m/s × 1.5s = 27m

y position = $\frac{27}{cos 35°}$ = 32.9709m (rounded up to nearest four decimal places)

After time is 2.0s:

Horizontal distance = 18m/s × 2.0s = 36m

y position = $\frac{36}{cos 35°}$ = 43.9479m (rounded up to nearest four decimal places)

3 0

4 years ago

PLEASE HELP!!!!!! the independent variable is associated mainly with? A. control and experimental groupsB. the treatment that th

Alex_Xolod [135]

The correct answer is B. The independent variable refers to what is being tested by a researcher in an experiment

Hope this helps

7 0

4 years ago

Read 2 more answers

A car's position in relation to time is plotted on the graph. What can be said about the car during segment B?

CaHeK987 [17]

we know that

the speed is equal to

$speed=\frac{distance}{time}$

The slope of the line on the graph is equal to the speed of the car

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

<u>the answer is the option B</u>

The car has come to a stop and has zero velocity

5 0

3 years ago

Read 2 more answers