Inflection at f'(x) = 0
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x^1/2 / (1 + x + x^3) = 0 </span>
<span>The x coordinate is x = 0 </span>
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or "C" from your choices there. </span>
<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
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x^1/2 / (some expression) </span>
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at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
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The denominator for x = 0 is 1 so you get </span>
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0/1 = 0.
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Answer:
0.75
Step-by-step explanation:
it makes sense that 3 is the Dividend, 4 is the Divisor, and you want to know the Quotient. Thus, the answer is:
3 ÷ 4 = 0.75
First, factor the (3y-4) and group the remaining terms
y²(3y-4) +7 (3y-4)
(y²+7)(3y-4)
I hope this helps (:
Start from inside to the out side of the function;
h(5)=10/5=2
g(h)=g(2)=3*2=6
now, get the f inverse of x;
f(x)=y=x+6
x=y-6
replace x with y and y with x
y=x-6
so f^-1= x-6
so f^-1(g)=f^-1(6)=6-6=0
I am not sure only of the last value, but pretty sure of the rest.
