The extra energy allows the molecules to convert states of molecules.
<h3>What is heating?</h3>
When the temperature is increased , the body or particle is said to be heating.
The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing.
When the liquid is converted to gas, the temperature reaches the boiling point of water. After boiling, the heat added up will only make the particles to convert its phase and go away in then atmosphere.
Thus, extra energy added helps molecules of water to change its state from liquid to solid.
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B . Because cardiovascular has everything to do with your heart how the blood flows and pumps and all that good stuff .
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:

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It depends on two factors height and mass
Answer:
a) W = 180.87 J
, b) ΔU = -180.87 J
, c) ΔU = -180.87 J
Explanation:
a) Work is defined as
W = F .ds
Where bold indicates vectors, we can write the scalar product
W = F s cos θ
Where the angle is between force and displacement.
The force of gravity is the weight of the body, which is directed downwards and the displacement thickens the tip of the cliff at the bottom, so that it is directed downwards, therefore the angle is zero degrees
W =
y
W = m g y
For this problem we must fix a reference system, from the statement it is established that the system is placed at the base of the cliff, so that final height is zero and the initial height (y₀ = 7.69m)
W = 2.40 9.8 (7.69-0)
W = 180.87 J
b) The potential energy is
U = mg y
The change in potential energy,
ΔU =
- U₀
ΔU = mg (
- y₀)
ΔU = 2.4 9.8 (0 -7.69)
ΔU = -180.87 J
c) in this case we change the reference system to the height of the cliffs, for this configuration
y₀ = 0
= -7.69 m
ΔU = 2.4 9.8 (-7.69 -0)
ΔU = -180.87 J