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3 years ago

7

In how many months will the total cost of both options be the same? What will that cost be?

1 answer:

gregori [183]3 years ago

7 0

If you make yourself a monthly expense chart:
   Months
<u> 1 2    3 4    5    6 7    8    9    10</u>
Opt 1 -80    -30    -30    -30    -30 -30    -30    -30 -30    -30
Opt 2 -40 -40    -40    -40 -40    -40    -40    -40    -40 -40

By month 5 the total amount spent for Opt 1 is $200 and Opt 2 is $200

For part two add up the values for each all the way up to month 9.
Option 1: 80 + 30(8) = 80 + 240 = 320 spent
Option 2: 40(9) = 360 spent

So option 1 is cheaper by month 9

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As reported in Trends in Television, the proportion of US households who have at least one VCR is 0.535. If 14 households are se

motikmotik

Using the binomial distribution, it is found that there is a 0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.

For each household, there are only two possible outcomes. Either it has at least one VCR, or it does not. The probability of a household having at least one VCR is independent of any other household, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

14 households, hence $n = 14$ .
0.535 probability of having at least one VCR, hence $p = 0.535$ .

The probability of <u>at least 6 and no more than 8</u> is:

$P(6 \leq X \leq 8) = P(X = 6) + P(X = 7) + P(X = 8)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{14,6}.(0.535)^{6}.(0.465)^{8} = 0.1539$

$P(X = 7) = C_{14,7}.(0.535)^{7}.(0.465)^{7} = 0.2024$

$P(X = 8) = C_{14,8}.(0.535)^{8}.(0.465)^{6} = 0.2038$

Then:

$P(6 \leq X \leq 8) = P(X = 6) + P(X = 7) + P(X = 8) = 0.1539 + 0.2024 + 0.2038 = 0.5601$

0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.

A similar problem is given at brainly.com/question/24863377

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Yuri [45]

Point B is located at (-6, 5)

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