How many molecules are in 62.01 grams of CO

1 answer:

7 0

62.01 g CO x (1 mol CO/ 28 g CO) = 2.2146...

28 g = 12 g (carbon) + 16 g (oxygen)

62.01 has 4 significant figures so the answer would be 2.215

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Using the formula M1V1 = M2V2 , how many milliliters of a 2. 50 M hydrochloric acid solution is required to make 100. 0 mL of a

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Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.

<h3>What is the relationship between molar concentration and dilution?</h3>

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$\begin{aligned}\rm V_{1} &= \rm \dfrac{M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.750 \times 100}{2.50}\\\\&= 30 \;\rm mL\end{aligned}$