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skad [1K]
3 years ago
15

How many molecules are in 62.01 grams of CO

Chemistry
1 answer:
Reptile [31]3 years ago
7 0
62.01 g CO x (1 mol CO/ 28 g CO) = 2.2146...

28 g = 12 g (carbon) + 16 g (oxygen)

62.01 has 4 significant figures so the answer would be 2.215
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For the reaction 3h2(g) + n2(g) 2nh3(g), kc = 9.0 at 350°c. calculate g° at 350°c.
miss Akunina [59]
When ΔG° is the change in Gibbs free energy

So according to ΔG° formula:

ΔG° =  - R*T*(㏑K)

here when K = [NH3]^2/[N2][H2]^3 = Kc 

and Kc = 9 

and when T is the temperature in Kelvin = 350 + 273 = 623 K

and R is the universal gas constant = 8.314 1/mol.K

So by substitution in ΔG° formula:

∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)

           = - 4536 
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3 years ago
Which option contains a correct statement about the size of
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Answer:

a molecule always has two or more atoms

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2 years ago
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Mama L [17]
1)
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2)
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Hope this Helps! :)

4 0
3 years ago
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