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Anastasy [175]
3 years ago
12

Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation: 12N2(g)+O

2(g)→NO2(g), ΔfH∘A=33.2 kJ mol−1 12N2(g)+12O2(g)→NO(g), ΔfH∘B=90.2 kJ mol−1
Chemistry
2 answers:
Alisiya [41]3 years ago
7 0
We apply Hess's Law and obtain:
2ΔHf(B) + ΔH(reaction) = 2ΔHf(A)
ΔH(reaction) = 2(33.2) - 2(90.2)
ΔH(reaction) = -114 kJ / mol
Alika [10]3 years ago
6 0

The enthalpy of the reaction : <u>114 kJ/mol</u>

<h3>Further explanation </h3>

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)

Determination of the enthalpy of formation of a reaction can be through a calorimetric experiment, based on the principle of Hess's Law, enthalpy of formation table, or from bond energy data

Delta H reaction (ΔH) is the amount of heat/heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The value of ° H ° can be calculated from the change in enthalpy of standard formation:

∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)

ΔH∘rxn = ΔH∘f of the product (s) if ∆Hf ° (reactants) = 0

<em>The elements in standard conditions are not included in the enthalpy calculations because the enthalpy of those elements under the standard conditions is zero. </em>

From the problem can be known

∆Hf ° NO₂ = 33.2 kJ / mol

∆Hf ° NO = 90.2 kJ / mol, so that

∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)

∆H ° rxn = 2.∆Hf ° NO₂ - 2. ∆Hf ° NO  (O₂ not included)

∆H ° rxn = 2.33.2 - 2.90.2

∆H ° rxn = 66.4 - 180.4

∆H ° rxn = -114 kJ / mol

<h3>Learn more </h3>

Delta H solution

brainly.com/question/10600048

an exothermic reaction

brainly.com/question/1831525

as endothermic or exothermic

brainly.com/question/11419458

an exothermic dissolving process

brainly.com/question/10541336

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C3H8(g) + 5O2(g) ⟶ 3CO2(g) + 4H2O(g) H = -2220 kJ If 865.9 g of H2O is produced during this combustion, how much heat is generat
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3 × 10⁴ kJ

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Step 2: Calculate the moles corresponding to 865.9 g of H₂O

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4. its atomic mass is 12.0107 u.

5. its melting and boiling point is 3550 °C and 4827 °C respectively.

Uses:

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3. it is also used in jewelry in the form of diamond and because of its hard nature used in industries for drilling, polishing, cutting and grinding.

4. carbon black powder is used in printer ink.

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