$\frac{8*( \frac{c}{c} )- \frac{3}{c} }{2*( \frac{7c}{7c})+ \frac{3}{7c} } \\ \\ \frac{ \frac{8c-3}{c} }{ \frac{14c+3}{7c} } \\ \\ \frac{8c-3}{c} * \frac{7c}{14c+3} \\ \\ = \frac{56c-21}{14c+3}$

Domain restrictions are what x values make the denominator zero.
a² + 5a - 36 = (a + 9)(a - 4)
a ≠ -9 ; a ≠ 4

6 0

2 years ago

In triangle RST, angle R is a right angle. If TR = 6 and TS = 8, what is the length of RS

lisabon 2012 [21]

Answer:

RS = 2 $\sqrt{7}$

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

RS² + RT² = TS² , that is

RS² + 6² = 8²

RS² + 36 = 64 ( subtract 36 from both sides )

RS² = 28 ( take the square root of both sides )

RS = $\sqrt{28}$ = $\sqrt{4(7)}$ = 2 $\sqrt{7}$ ≈ 5.3 ( to 1 dec. place )

8 0

2 years ago

Which is the slope of the line that passes through the points (3,17) and (7,25)? a slope = 1/2 b slope = 2 c slope = −2 d slope

Ierofanga [76]

Slope is y2-y1/x2-x1
so, 25-17/7-3
8/4=2
The answer should be b

5 0

2 years ago

Suppose that x and y vary inversely and that y = 5 when x = 1. What is y when x = 15?

LiRa [457]

Answer:

Y=1/3

Step-by-step explanation:

X=k/y

So let's make k the subject of formula

k=xy

x=1,y=5

So let's substitute

k=1×5

k=5

So we are to determine the value for y when x is 15

So let's solve

Y=k/x

Y=5/15

Y=1/3

Y=0.333333~0.3

7 0

2 years ago