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2 years ago

What is the weight of a 63.7 kg person?

Physics

2 answers:

dybincka [34]2 years ago

7 0

Answer: 140.4 pounds

Explanation:

IRINA_888 [86]2 years ago

6 0

Answer:

A person that weighs 63.7 kg weighs 63.7 kg

Explanation:

Too complicated to explain.

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A 150 g egg is dropped from 3.0 meters. The egg is

Lynna [10]

Answer:

9.2 N, with significant figure rounding (2 s.f.)

Explanation:

This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:

Note that where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.

Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg.

m = 0.15 kg

The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.

v₀ = 4.4 m/s [down]

When it comes to a stop, the egg will have a velocity of 0.

v = 0 m/s

The time it takes for the egg to stop is 0.072 seconds.

Δt = 0.072 s

Therefore, if down is positive, then

We round to two significant figures since every quantity has two sig. figs.

We only care about the magnitude, not direction. The answer is 9.2 N.

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5.0

5 0

2 years ago

Help ASAP plssssssssss

garik1379 [7]

C. 32400 because 540 * 60 = 32400

5 0

3 years ago

How is the atomic mass of an atom determined?

Ipatiy [6.2K]

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom

5 0

2 years ago

An object has an acceleration of 12.0 m/s/s. If the mass of this object were tripled (with no change in its net force), then its

yaroslaw [1]

Answer:

If it is triple it means we multiply it by 3 then it is 36.3 m/s/s

8 0

3 years ago

A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cr

Musya8 [376]

Answer:

162500000.

Explanation:

Given that

Diameter of the wire , d= 1.8 mm

The length of the wire ,L = 15 cm

Current ,I = 260 m A

The charge on the electron ,e= 1.6 x 10⁻¹⁹ C

We know that Current I is given as

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

q= I t

q= 260 m t

The total number of electron = n

q= n e

$n=\dfrac{260\times 10^{-3}\ t}{1.6\times 10^{-9}}$

n=162500000 t

$\dfrac{n}{t}=16250000$

The number of electron passe per second will be 162500000.

4 0

2 years ago