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mafiozo [28]
3 years ago
11

The brakes of a 125 kg sled are applied while it is moving at 8.1 m/s, which exerts a force of 261 N to slow the sled down. How

far does the sled travel while coming to a stop in meters? Round to one decimal place.
Physics
1 answer:
sammy [17]3 years ago
6 0

Answer:

15.7 m

Explanation:

m = mass of the sled = 125 kg

v₀ = initial speed of the sled = 8.1 m/s

v = final speed of sled = 0 m/s

F = force applied by the brakes in opposite direction of motion = 261

d = stopping distance for the sled

Using work-change in kinetic energy theorem

- F d = (0.5) m (v² - v₀²)

- (261) d = (0.5) (125) (0² - 8.1²)

d = 15.7 m

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Based on what you learn about jovian moons by watching the videos or reading your textbook, what types of evidence for recent or
Valentin [98]

Answer:

b. craters, river valleys feeding into surface lakes of very cold liquids

Explanation:

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7 0
3 years ago
Fluorescence occurs when an object absorbs ____________________ and immediately releases the energy as visible light.
soldier1979 [14.2K]

Answer:

The answer should be light or other electromagnetic radiation

Explanation:

Such as x-rays or other things like that.

<em>-Hope This Helps!</em>

<em>-Justin:)</em>

5 0
2 years ago
An archer fires an arrow at a castle 230 m away. The arrow is in flight for 6 seconds, then hits the wall of the castle and stic
Vika [28.1K]

Answer:

(a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

Explanation:

Given that,

Horizontal distance = 230 m

Time t = 6 sec

Vertical distance = 16 m

We need to calculate the horizontal component

Using formula of horizontal component

R =u\cos\theta t

Put the value into the formula

\dfrac{230}{6} = u\cos\theta

u\cos\theta=38.33.....(I)

We need to calculate the height

Using vertical component

H=u\sin\theta t-\dfrac{1}{2}gt^2

Put the value in the equation

16 =u\sin\theta\times6-\dfrac{1}{2}\times9.8\times6^2

u\sin\theta=\dfrac{16+9.8\times18}{6}

u\sin\theta=32.06.....(II)

Dividing equation (II) and (I)

\dfrac{u\sin\theta}{u\cos\theta}=\dfrac{32.06}{38.33}

\tan\theta=0.8364

\theta=\tan^{-1}0.8364

\theta=39.90^{\circ}

(a). We need to calculate the initial speed

Using equation (I)

u\cos\theta\times t=38.33

Put the value into the formula

u =\dfrac{230}{6\times\cos39.90}

u=49.96\ m/s

(b). We have already calculate the angle.

Hence, (a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

5 0
3 years ago
A river flows due east at 12 km/h. A boat crosses the 720 m wide river by maintaining a constant velocity of 72 mi/h due north r
zhenek [66]

Answer:

The boat will be 74 .17 meters downstream by the time it reaches the shore.

Explanation:

Consider the vector diagrams for velocity and distance shown below.

converting 72 miles per hour to km/hr

we have 72 miles per hour 72 × 1.60934 = 115.83 km/hr

The velocity vectors form a right angled triangle, and can be solved using simple trigonometric laws

tan \theta = \frac{12}{115.873}

\theta = tan^{-1}(  \frac{12}{115.873})=5.9126

This is the vector angle with which the ship drifts away with respect to its northward direction.

<em>From the sketch of the displacement vectors,  we can use trigonometric ratios to determine the distance the boat moves downstream.</em>

Let x be the distance  the boat moves downstream.d

sin(5.9126)=\frac{x}{720}

x= 720\times 5.9126

x=74.17m

∴The boat will be 74 .17 meters downstream by the time it reaches the shore.

6 0
3 years ago
A charge of 90 C passes through a wire in 1 hour 15 minutes . what is the current in the wire
timurjin [86]
We calculate current from the formula:
I= \frac{q}{t} , where q is a electric charge transferred over time t 
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I=\frac{90C}{4500s}=0,02A Result is in unit-Ampere
5 0
3 years ago
Read 2 more answers
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