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Mashutka [201]
2 years ago
8

In Fig. on the right, what is the acceleration at 1.0 s?

Physics
2 answers:
AleksAgata [21]2 years ago
7 0

Answer:

10m/s2

Explanation:

Acceleration is defined as change in velocity over the time period

Now at 1second the velocity is 10m/s.

Hence the acceleration is V-U/t;

Where V is velocity at 10s and U is velocity when the object is at rest.

So we have;

Acceleration = 10-0/ 1 = 10m/s2

maks197457 [2]2 years ago
3 0

Answer:

10 m/s²

Explanation:

Acceleration is the slope of the velocity vs time graph.

At t = 1.0 s, the slope of the line is:

a = Δv/Δt

a = (20 m/s) / (2.0 s)

a = 10 m/s²

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The diameter of a copper atom is approximately 2.28e-10 m. The massof one mole of copper is 64 grams. Assume that the atoms area
KIM [24]

1) Mass of one copper atom: 1.063\cdot 10^{-22} kg

2) There are 9.33\cdot 10^{24} atoms in the cube

3) Mass of the cubical block: 992 kg

Explanation:

1)

We are told here that the mass of one mole of copper is

M=64 g

for

n=1 mol (number of moles)

We also know that the number of atoms inside 1 mole of substance is equal to Avogadro number:

N_A = 6.022\cdot 10^{23}

This means that N_A atoms of copper have a mass of M = 64 g. Therefore, we can find the mass of one copper atom by dividing the total mass by the avogadro number:

m=\frac{M}{N_A}=\frac{64}{6.022\cdot 10^{23}}=1.063\cdot 10^{-22} kg

2)

We are told that the diameter of a copper atom is

d=2.28\cdot 10^{-10} m

We can assume that the atoms are arranged in a cube, and that they are all attached to each other; so the side of the cube can be written as size of one atom multiplied by the number of atom per side:

L=Nd

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N is the number of atoms (rows) in one side of the cube

Since the side of the cube is

L = 4.8 cm = 0.048 m

We find N:

N=\frac{L}{d}=\frac{0.048}{2.28\cdot 10^{-10}}=2.11\cdot 10^8

This is the number of atom rows per side; therefore, the total number of atoms in the cube is

N^3=(2.11\cdot 10^8)^3=9.33\cdot 10^{24}

3)

The total mass of the cubical block of copper will be given by the mass of one atom of copper multiplied by the total number of atoms, so:

M= N^3 m

where:

N^3 = 9.33\cdot 10^{24} is the number of atoms in the cube

m=1.063\cdot 10^{-22} kg is the mass of one atom

Therefore, substituting, we find:

M=(9.33\cdot 10^{24})(1.063\cdot 10^{-22})=992 kg

So, the mass of the cubical block is 992 kg.

Learn more about mass and density:

brainly.com/question/5055270

brainly.com/question/8441651

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the area of 1 end of U-tube is 0.0 metre square and that of the other end is 1 metre square when you force was applied on the li
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