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Furkat [3]
2 years ago
8

What happens to a solid if thermal energy is reduced

Chemistry
1 answer:
kompoz [17]2 years ago
8 0
When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.
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Why is baking soda an ionic bond
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Because it is made up of sodium, a metal, and carbon, a nonmetal.

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3 years ago
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A 3.56 L balloon is compressed to 1.00 L at constant temperature. If the initial pressure in the balloon was 101.3 kPa, what is
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3 years ago
5 points IF U ANSWER THE QUESTION CORRECTLY
asambeis [7]

Answer:

No matter how well how much you accomplish, or how much good you put into the world, you will always have haters. An unfortunate aspect of life is that some people hate when others do well.It’s just a way of life.some people just are jealous but dont let people brake you down.

Explanation:

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6 0
2 years ago
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A slender uniform rod 100.00 cm long is used as a meter stick. two parallel axes that are perpendicular to the rod are considere
kvv77 [185]
Refer to the diagram shown below.

The second axis is at the centroid of the rod.
The length of the rod is L = 100 cm = 1 m

The first axis is located at 20 cm = 0.2 m from the centroid.
Let m =  the mass of the rod.

The moment of inertia about the centroid (the 2nd axis) is
I_{g} =  \frac{mL^{2}}{12} = (m \, kg) \frac{(1 \, m)^{2}}{12} =  \frac{m}{12} \, kg-m^{2}

According to the parallel axis theorem, the moment of inertia about the first axis is
I_{1} = I_{g} + (m \, kg)(0.2 m)^{2} \\ I_{1} =  \frac{m}{12}+ 0.04m = 0.1233m \, kg-m^{2}

The ratio of the moment of inertia through the 2nd axis (centroid) to that through the 1st axis is
\frac{I_{g}}{I_{1}} =  \frac{0.0833m}{0.1233m} =0.6756

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6 0
3 years ago
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Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc
kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

Percentage Error=\frac{Error}{AcceptedValue} X100

Maximum allowed value of percentage error = 10%

put this value in the equation in stead of percentage error we get,

10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value

so maximum error = .1 x accepted value

10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value

or .1 times of accepted value

8 0
3 years ago
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