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Paraphin [41]
3 years ago
13

19. When baking soda and vinegar are combined, the result is a salt called sodium acetate. This forms

Physics
1 answer:
Orlov [11]3 years ago
3 0
It is a chemical change because the baking soda and vinegar are reacting to form a new product.
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Imagine you have just witnessed a small avalanche on a mountain while skiing, and two slushy snowballs just crashed together in
inn [45]
We have that the momentum p is given by the formula p=mv where m is the mass and v is the velocity. Since for A p=-14kgm/s and m=7, we have that the velocity is -14/7=-2m/s. Hence its speed is 2 m/s.
For b we have that p=15kgm/s and v=3m/s. Because m=p/v, we have m=3kg.
We also have that the momentum is conserved in this system. Hence, the net sum of the momentum of the 2 snowballs equals the momentum of the single giant ball. Hence, p(total)=p(combined)=-14+15=1kgm/s (momentum is a vector; the positive sign means that it tends to the positive direction).

6 0
4 years ago
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Order these sounds from loudest (1)
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Answer:

1. Airplane

2. Crowd at sporting

3. Event

4. Rainfall

5. Whisper

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3 years ago
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Can someone please help me with some physics​
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6 0
3 years ago
A 25kg crate is at rest on a floor but is pushed by a force of 60N to the right . If the crate remains at rest, determine the co
Ymorist [56]

Ff=μN=>μ=Ff/N=Ff/mg=60/25*10=6/25=0.24

3 0
4 years ago
An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave
klemol [59]

Answer:u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}

Explanation:

Given

height of building h=3 m

Landing velocity of diver v=8.90 m/s at an angle of 75^{\circ}

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

u\cos \theta =8.9\cos (75)        ---- -----1

Considering Vertical motion

v^2-u^2=2as

here v=8.9\sin (75)

u=u\sin \theta

s=3 m

a=9.8 m/s^2

(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3

u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}

u\sin \theta =3.886         ----------------2

Divide 2 and 1 we get

\tan \theta =\frac{3.886}{8.9\cos (75)}

\tan \theta =1.687

\theta =59.34^{\circ}

Thus u\cos (59.34)=8.9\cos (75)

u=4.51 m/s

7 0
3 years ago
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