The amount of heat needed would be the specific heat multiplied by the mass of the substance and the temperature difference. In this case, the mass would be 75.0–g, the specific heat would be 0.449 j/g °c, and the temperature difference would be <span>1535 -25= 1510
Then the calculation would be: </span>0.449 j/g °c * 75g * 1510°c = 50,849.25J
In calorie it would be: 50849.25J / 4.184J/cal= 12,153.26 calorie
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Answer:
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Answer:
2NH4NO3 —> 2N2 + O2 + 4H2O
Explanation:
We begin by writing the skeletal equation as shown below:
NH4NO3 —> N2 + O2 + H2O
The equation can be balance as follow:
There are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:
NH4NO3 —> N2 + O2 + 2H2O
Now we have a total of 4 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 1/2 in front of O2 as shown below:
NH4NO3 —> N2 + 1/2O2 + 2H2O
Now, multiply through by 2 to clear the fraction as shown below
2NH4NO3 —> 2N2 + O2 + 4H2O
Now the equation is balanced
Answer:
If the hydrated salt is overheated, it causes the anhydrous salt to decompose, causing the product to be lost as gas. The reported percentage of water loss will be too high because the gap between the initial measurement and final (which will be lower due to loss of sample) measurement will widen.