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Leto [7]
3 years ago
14

A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylin

der after the borax solution had cooled to a certain temperature T. The student rinses the sample into a small beaker using distilled water, and then titrates the solution with a 0.500 M HCl solution. 12.00 mL of the HCl solution is needed to reach the endpoint of the titration.
Calculate the value of Ksp for borax at temperature T. (Answer: 0.176 Show your work.)

Here is a suggested procedure for doing this calculation:

(a) Calculate the number of moles of HCl that were added during the titration.

(b) Use reaction (2) in the lab manual to relate the number of moles of HCl to the number of moles of tetraborate ion in the 8.50 mL sample.

(c) Calculate the concentration of tetraborate ions in the 8.50 mL sample.

(d) Use reaction (1) in the lab manual to relate the concentration of tetraborate ions to the concentration of sodium ions.

(e) Use the concentrations of tetraborate ions and sodium ions to calculate the equilibrium constant (Ksp) at temperature T for reaction (1) in the lab manual.
Chemistry
1 answer:
belka [17]3 years ago
6 0

Answer:

Ksp = 0.1762

Explanation:

Applying

a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol

b) since 0.006mol is present in 0.012dm3 of HCl

It implies moles of borax

C) Concentration = 0.706M

Ksp = [0.5]^2[0.706]= 0.176

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Convert 5.4g of NaCl to moles
sammy [17]

Answer:

.0924 moles of NaCl

Explanation:

So you know you have 5.4 g of NaCl and you need to know how many moles there are in this amount of NaCl

  1. You'll need to find the atomic mass of the compound NaCl to help you solve for moles
  • Sodium (Na) on the periodic table has a mass of 22.99
  • Chlorine (Cl) on the periodic table has a mass of 35.45

Add these two together----> 22.99 + 35.45 = 58.44

Now you can calculate for moles

<u>Written-out method:</u>

<u>5.4 grams of NaCl  |   1 mole of  NaCl              </u>

                                | 58.44 grams NaCl                = .0924 moles of NaCl

<u>Plug into calculator method:</u>

(5.4 g of NaCl/ 58.44g NaCl= .0925 moles)

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