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Leto [7]
3 years ago
14

A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylin

der after the borax solution had cooled to a certain temperature T. The student rinses the sample into a small beaker using distilled water, and then titrates the solution with a 0.500 M HCl solution. 12.00 mL of the HCl solution is needed to reach the endpoint of the titration.
Calculate the value of Ksp for borax at temperature T. (Answer: 0.176 Show your work.)

Here is a suggested procedure for doing this calculation:

(a) Calculate the number of moles of HCl that were added during the titration.

(b) Use reaction (2) in the lab manual to relate the number of moles of HCl to the number of moles of tetraborate ion in the 8.50 mL sample.

(c) Calculate the concentration of tetraborate ions in the 8.50 mL sample.

(d) Use reaction (1) in the lab manual to relate the concentration of tetraborate ions to the concentration of sodium ions.

(e) Use the concentrations of tetraborate ions and sodium ions to calculate the equilibrium constant (Ksp) at temperature T for reaction (1) in the lab manual.
Chemistry
1 answer:
belka [17]3 years ago
6 0

Answer:

Ksp = 0.1762

Explanation:

Applying

a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol

b) since 0.006mol is present in 0.012dm3 of HCl

It implies moles of borax

C) Concentration = 0.706M

Ksp = [0.5]^2[0.706]= 0.176

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commercial cold packs consist of solid NH4NO3 and water. In a coffee-cup calorimeter, 5.60g NH4NO3 is dissolved in 100g of water
fgiga [73]

Answer:

-1.37 kJ/mol

Explanation:

The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 5.60 g

Specific heat = 4.18 J/g°C

\Delta T=17.9-22.0\ ^0C=-4.1\ ^0C

So,  

\Delta H=-1.25\times 4.18\times 3.9\ J=-95.9728\ J

Negative sign signifies loss of heat.  

Also, 1 J = 0.001 kJ

So,  

\Delta H=-0.096\ kJ

Also,

Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{5.60\ g}{80.043 \ g/mol}

Moles= 0.06996\ mol

Thus, \Delta H=-\frac{0.096}{0.06996}\ kJ/mol=-1.37\ kJ/mol

6 0
4 years ago
Consider the following mechanism for the formation of tert-butanol: (CH_3)_3CBr(aq) rightarrow (Ch_3)_3 C^+ (aq) + Br^- (aq) (CH
Sloan [31]

Answer:

The mechanism is in the attached file. The reaction intermediates are the following: C4H8O, C4H9O

Explanation:

Terbutanol is a tertiary alcohol. It is one of the four isomers of butanol. It is a transparent liquid (or a colorless solid, depending on the temperature), with an odor similar to camphor. It is very soluble in water and ethanol.

The scheme shows a protonation of the double bond and the nucleophilic attack of the water to the carbocation, then it loses a proton and the terbutanol is formed.

Download pdf
4 0
3 years ago
A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.
julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0
4 years ago
The r group or side chain of the amino acid serine is –ch2 -oh. the r group or side chain of the amino acid alanine is – ch3 . w
olya-2409 [2.1K]
Ch 5 protein mainfactured by solution
8 0
4 years ago
If you are given an ideal gas with pressure (P) = 259,392.00 Pa and temperature (T) = 2.00 oC of 1 mole Argon gas in a volume of
3241004551 [841]

Answer:

 R = 0.064 dm³ atm K⁻¹ mol⁻¹

Explanation:

Answer:

Explanation:

Data Given:

volume of gas V = 8.8 dm³

no. of mole of gas (n) = 1 mole

Pressure P = 259,392.00 Pa  

Convert Pascal (Pa) to atm (atmospheric pressure)

As

101,325 Pascals = 1 atm

So,

259,392.00 Pa  = 2 atm

Then Pressure (P) = 2 atm

Temperature T = 2.00 °C  

change the temperature from °C to K

As  to convert °C to K the below formula used

                   0°C + 273.15 = 273.15K

So, for 2 °C

                    2°C  + 273.15 =  275.15 K

So,

Temperature T  = 275.15 K

ideal gas constant = ?

formula used for Ideal gases

                            PV = nRT

as we have to find R of the gas:

we will rearrange the ideal gas equation as below:

R = PV / nT ........................................... (1)

Put value in equation (1)

                 R = 2atm x 8.8 dm³ / 1 mole x 275.15 K

                  R = 17.6 atm. dm³ / 275.15 mol. K

                  R = 0.064 dm³ atm K⁻¹ mol⁻¹

So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹

and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹

7 0
3 years ago
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