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3 years ago

Solve these Please. (15 points)

Chemistry

1 answer:

Ghella [55]3 years ago

3 0

Answer:

1) 4Fe + 3O2 → 2Fe2O3

2) H2 + Cl2 → 2HCl

3) 2Ag + H2S → Ag2S + H2

4) CH4 + 2O2 → CO2 + 2H2O

5) 2HgO → 2Hg + O2

6) 2Co + 3H2O → Co2O3 + 3H2

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A sample of 14.5 g of sodium bicarbonate (NaHCO3) was dissolved in 100 ml of water in a coffee-cup calorimeter with no lid by th

Ann [662]

Answer:

The ΔH of the reaction is + 12.45 KJ/mol

Explanation:

Mass of water= 100ml = 100g. (You should always assume 1cm3 of water as 1g)

heat capacity of water = 4.18 Jk-1 Mol-1

Change in temperature = (19.86 - 25.00) = -5.14 K (This is an endothermic reaction because of the fall in temperature)

Molar mass of NaHCO3 = 84 g/mol

Mole of NaHCO3 = 14.5 / 84 = 0.173 mol

Step 1 : Calculate the heat energy (Q) lost by the water.

Q = M x C x ΔT

Q = -100 x 4.18 x (-5.14)

Q = 2148.5 joules

Q = 2.1485 K J

Step 2: Calculating the ΔH of the reaction?

ΔH = Q / number of moles of NaHCO3

ΔH = 2.1485 / 0.173

ΔH = 12.42 KJ/mol

3 0

3 years ago

I NEED HELP!!! I WILL RATE BRAINLIEST!!!!

icang [17]

It is 3 moles. Don't doubt urself

4 0

4 years ago

What is the distinction between the caus and the manner of death

kompoz [17]

The manner of death is how the death came about. A natural death occurs as a result of aging, illness, or disease. ... A homicide occurs when death is caused by another person.

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3 years ago

Consider the solubilities of a particular solute at two different temperatures. Temperature ( ∘ C ) Solubility ( g / 100 g H 2 O

grin007 [14]

Answer:

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water = $\frac{32.2}{100}g=0.322 g$

Mass of solute in soluble in 56.0 grams of water:

$0.322\times 56.0=18.032 g$

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water = $\frac{70.2}{100}g=0.702 g$

Mass of solute in soluble in 56.0 grams of water:

$0.702 \times 56.0=39.312 g$

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.

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3 years ago

select all the correct answers. Which conditions are required for nuclear fusion to begin? The gas cloud must be very dense. Gra

Nimfa-mama [501]

Answer:

The gas cloud must be very dense.Temperatures must exceed 14 million Kelvin

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4 years ago

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