Answer:
7revolutions
Explanation:
Given parameters:
Initial revolution = 250rpm
Final revolution = 150rpm
Time = 4.2s
Unknown:
Number of revolutions that occur at this time = ?
Solution:
To solve this problem;
let us find the change in revolution = 250rpm - 150rpm = 100rpm
Convert the time to seconds;
60s makes 1 minute
4.2s will make 
= 0.07min
So;
The number of revolutions at this time = 100rpm x 0.07min
= 7revolutions
B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
<h3>When external ear squeeze occurs</h3>
External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.
Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
Learn more about ear squeeze here: brainly.com/question/11430998
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:D HI YOUR ANSWER WOULD BE 8 NEWTONS TO DA RIGHT
22N to right + 14N to left
Answer:
<h2> 0.041kg</h2>
Explanation:
Step one:
given data
initial velocity u= 0m/s
Force F= 443N
time t= 4.3 ms= 0.0043seconds
final velocity v= 45.7m/s
Step two:
Required
mass m
we know that the expression for impulse is given as
Ft=mv
make m subject of the formula
m=Ft/v
substitute we have
m=443*0.0043/45.7
m=1.90/45.7
m=0.04kg
The mass of the ball is 0.041kg
Answer:
C) Pnew=Poriginal/9
Explanation:
From the given conditions:
Original area, 
New area of the barrel bottom panel after increasing by a factor of 3:
On increasing the radius the area now becomes:
As we know that there will be no increase in the down-force since the height remains constant.
Pressure is given as:
∴New pressure:
