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Alekssandra [29.7K]
3 years ago
13

ASAP PLEASE HELP , Ill give you what you want

Physics
1 answer:
Alik [6]3 years ago
7 0
Force of friction is applied,
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A flywheel flows from 250rpm to 150rpm in 4.2 seconds. How many revolutions occur during this time ​
Assoli18 [71]

Answer:

7revolutions

Explanation:

Given parameters:

Initial revolution  = 250rpm

Final revolution  = 150rpm

Time  = 4.2s

Unknown:

Number of revolutions that occur at this time = ?

Solution:

To solve this problem;

 let us find the change in revolution  = 250rpm - 150rpm  = 100rpm

Convert the time to seconds;

         60s makes 1 minute

        4.2s will make \frac{4.2}{60}   = 0.07min

So;

      The number of revolutions at this time  = 100rpm x 0.07min

         =   7revolutions

6 0
4 years ago
An ear squeeze occurs when: Select one: The pressure inside the middle ear space is greater than ambient (surrounding) pressure.
matrenka [14]

B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.

<h3>When external ear squeeze occurs</h3>

External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.

Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.

Learn more about ear squeeze here: brainly.com/question/11430998

#SPJ1

6 0
2 years ago
What is the net force on this object?
Anna35 [415]
:D HI YOUR ANSWER WOULD BE 8 NEWTONS TO DA RIGHT
22N to right + 14N to left 
3 0
3 years ago
Read 2 more answers
When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Sindrei [870]

Answer:

<h2> 0.041kg</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

m=0.04kg

The mass of the ball is 0.041kg

6 0
3 years ago
The pressure at the bottom of a full barrel of water is Poriginal. Determine what happens to the pressure when the radius or hei
erastovalidia [21]

Answer:

C) Pnew=Poriginal/9

Explanation:

From the given conditions:

Original area, A_o=\pi.r_o\,^2

New area of the barrel bottom panel after increasing by a factor of 3:

r_{new}=3r_o

On increasing the radius the area now becomes:

A_{new}=\pi.(3r_o)^2

A_{new}=9\pi.(r_o)^2=9A_o

As we know that there will be no increase in the down-force since the height remains constant.

Pressure is given as:

P_{original}=\frac{Force}{A_o}

∴New pressure:

P_{new}=\frac{Force}{9A}

\Rightarrow P_{new}=\frac{P_{original}}{9}

4 0
3 years ago
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