Answer:
45.04 cm
Explanation:
The tired physics professor red easily at a distance of 26 cm
So v = 26 cm
And it is given that object distance that is u = 61.5 cm
There is relation between focal length object distance and image distance that is 
Here f =focal distance v = image distance and u = object distance
So 
So f=45.04 cm
Potential energy, is energy due to its position.
Given: Mass m = 40 Kg; Height h = 50 m
Required: Potential energy P.E = ?
Formula: P.E = mgh P.E = (40 Kg)(9.8 m/s²)(50 m)
P.E = 19,600 J
Answer:

Explanation:
For this exercise let's use hooke's law
F = - k x
where x is the displacement from the equilibrium position.
x =
if we have several springs in series, the total displacement is the sum of the displacement for each spring, F the external force applied to the springs
x_ {total} = ∑ x_i
we substitute
x_ {total} = ∑ -F / ki
F / k_ {eq} = -F
1 / k_ {eq} = ∑ 1 / k_i
if all the springs are the same
k_i = k


