The answer to the question is gonna be A
Answer:
The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.
Explanation:
Maximum speed is :
v (max) = Aω
Speed v at any displacement y is given by
= 
(
- 
) ........................................................ i
And,
v = 
v (max)
or, 2 × v = Aω .................................................... ii
Eliminating ω from equations i and ii,
= ( - )
or, = (
) =() 
or, y = 3.56 cm.
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
Answer:
The correct answer is D.
D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.
Explanation:
Glare is produced on a computer screen when light from some external source reflects on the screen.
Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.
