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laiz [17]
3 years ago
7

Please help and thank you

Physics
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

B. C3H8

Chemical Formula for propane is C3H8

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Es muy común que cuando se viaja hacia un río o lago se juegue "ranita", el cual consiste en lanzar una piedra horizontalmente h
shutvik [7]

Answer:

a) La piedra es lanzada desde una altura de 0,785 metros.

b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Explanation:

a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:

y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2} (1)

Donde:

y - Altura final, medida en metros.

y_{o} - Altura inicial, medida en metros.

v_{o,y} - Componente vertical de la velocidad inicial, medida en metros por segundo.

t - Tiempo, medido en segundos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que y = 0\,m, v_{o,y} = 0\,\frac{m}{s}, t = 0,4\,s y g = -9,807\,\frac{m}{s^{2}}, entonces la altura inicial de la piedra es:

y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}

y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}

y_{o} = 0,785\,m

La piedra es lanzada desde una altura de 0,785 metros.

b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:

v_{o,x} = \frac{x-x_{o}}{t} (2)

Donde:

x_{o}, x - Posiciones horizontales iniciales y finales, medidas en metros.

t - Tiempo, medido en segundos.

Si tenemos que x_{o} = 0\,m, x = 2,5\,m y t = 0,4\,s, entonces el componente horizontal de la velocidad inicial es:

v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}

v_{o,x} = 6,25\,\frac{m}{s}

La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

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