Answer:
The magnitude and direction of the force between the two charges is 497.66 N in opposite direction.
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 1.4×10¯³ C
Charge 2 (q₂) = 9.1×20¯⁴ C
Distance apart (r) = 4.8 m
Force (F) =?
NOTE: Electric constant (K) = 9×10⁹ Nm²/C²
The magnitude of the force between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 1.4×10¯³ × 9.1×20¯⁴ / 4.8²
F = 11466 / 23.04
F = 497.66 N
Thus, the magnitude of the force is 497.66 N.
Since both charges has the same sign (i.e they both positive), the force between them will be a force of repulsion. Hence the force will be in opposite direction.
The dependence of a measured value on a controlled value should be the correct answer.
Protons neutron electrons
