We are told that KOH is being used to completely neutral H₂SO₄ according to the following reaction:
KOH + H₂SO₄ → H₂O + KHSO₄
If KOH can completely neutralize H₂SO₄, then there must be an equal amount of moles of each as they are in a 1:1 ratio:
0.025 L x 0.150 mol/L = .00375 mol KOH
0.00375 mol KOH x 1 mole H₂SO₄/1 mole KOH = 0.00375 mol H₂SO₄
We are told we have 15 mL of H₂SO₄ initially, so now we can find the original concentration:
0.00375 mol / 0.015 L = 0.25 mol/L
The concentration of H₂SO₄ being neutralized is 0.25 M.
Explanation:
1g = 1000mg
154000mg = 154g
No of days she can drink = 154÷ 11 = 14days
Answer: The last electron will be filled in first orbital of 3p sub-shell.
Explanation: Filling of electrons in orbitals is done by using Hund's Rule.
Hund's rule states that the electron will be singly occupied in the orbital of the sub-shell before any orbital is doubly occupied.
For filling up of the electrons in Sulfur atom having 16 electrons. First 10 electrons will completely fill according to Aufbau's Rule in 1s, 2s and 2p sub-shells and last 6 electrons are the valence electrons which will be filled in the order of 3s and then 3p.
3s sub-shell will be fully filled and the orbitals of 3p sub-shell will be first singly occupied and then pairing will take place. Hence, the last electron will be filled in the first orbital of 3p-sub-shell.
At l = 3, ml =+3,+2,+1,0,-1,-2,-3
What are quantum numbers?
- Quantum numbers are used to describe where around a nucleus a particular electron can be found.
- In any given atom, each electron can be described by four quantum numbers.
- These are n,l,m1,ms
- The values that each number can be are based on a set of rules.
What is a magnetic quantum number ?
- It describes the orientation of the orbitals.
- It is represented as ml.
- The value of this quantum number ranges from (-l to +l).
- When l = 2, the value of will be -2, -1, 0, +1, +2.
To know more about magnetic quantum numbers, refer:
brainly.com/question/14650566
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What is the percent composition by mass of oxygen in magnesium oxide, MgO?
Answer: 39.7 percent