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jeka94
3 years ago
8

A 2.0 kg mass weighs 10 Newtons on planet X. what is the acceleration due to gravity on planet X? Show the work.

Physics
1 answer:
KengaRu [80]3 years ago
8 0

Answer: The gravitational acceleration on planet X is 5 N/kg

On Earth (with the gravitational accelartion g_E) the mass of 2kg will correspond to

F_E = m\cdot g_E = 2.0 \mbox{kg}\cdot 9.8 \frac{N}{kg} = 19.6 N

On planet X we are told the same measure is only 10N. Since there is a proportional relationship between g and F, we can calculate g_X:

\frac{F_E}{g_E}=\frac{F_X}{g_X} \implies\\g_x = \frac{g_E\cdot F_X}{F_E}=\frac{9.8 N/kg \cdot 10 N }{19.6N}=5 \frac{N}{kg}

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Crew members attempt to escape from a damaged submarine 141 m below the surface.What force must be applied to a pop-out hatch, w
AfilCa [17]

Answer:

20.9 x 10⁵ N

Explanation:

The external air pressure downwards and internal air pressure upwards will cancel out. TH net pressure to be faced will be due to water column of 141 m depth.

Pressure of water = hdg = 141 x 1024 x 9.8 = 14.15 x 10⁵ Pa

Area of hatch = 1.72 x 0.859 = 1.4775 sq m.

Total force required = area x pressure = 14.15 x 10⁵ x 1.4775 = 20.9 x 10⁵ N.

3 0
3 years ago
1. What quantity of heat is required to raise?
netineya [11]

Answer: Calculate the energy required in joules to raise the temperature of 450 grams of water from 15°C to 85°C? (The specific heat capacity of water is 4.18 J/g/°C)

Explanation:

8 0
3 years ago
In a position time graph, a curved line represents: acceleration no movement constant velocity
Mumz [18]

Answer:

acceleration or a deceleration

Explanation:

The gradient of a position -  time graph represent the velocity.

a straight line indicate a constant velocity (gradient ≠ 0)

when it is a parallel line to the time axis , it indicated no movement

when it is a curved line it indicates a changing velocity (either acceleration or a deceleration) as mentioned in the graph

4 0
3 years ago
1) An object is dropped from the top of tower of hight 156.8m and at the same time another object is thrown vertically upward wi
Anton [14]

Answer:

The objects meet after 2.033722438s, at a height 136.5334679m from the ground.

Explanation:

Call the object being dropped A and the object being thrown B.

When the objects meet, the time ('t') for both objects will be equal, and the sum of their distances will be equal to 156.8m.

Figure out the distance for A in terms of time, t:

s = ut + (1/2)at²

= 0t +(1/2)(9.8)t²

=4.9t²

Figure out the distance for B in terms of time, t:

s = ut + (1/2)at²

=(77.1)t + (1/2)(-9.8)t²

=77.1t - 4.9t²

We now adding the distances gives us 156.8, so can write:

(4.9t²) + (77.1t - 4.9t²) = 156.8

77.1t = 156.8

∴ t = 2.033722438s

To find the distances, plug in this value for t:

For A: 4.9t² → 20.26653209m

For B: 77.1t - 4.9t² → 136.5334679m

8 0
3 years ago
A 5.0 μf and a 7.0 μf capacitor are connected in series across an 8.0-v dc source. What is the voltage across the 5.0 μf capacit
Semmy [17]

Answer:4.67 V

Explanation:

Given

C_1=5\ \muf

C_2=7\ \muf

Voltage V=8\ V

For capacitance in series Net capacitance is given

C_{net}=\frac{C_1\cdot C_2}{C_1+C_2}

C_{net}=\frac{5\times 7}{5+7}=\frac{35}{12} \muf

q=C_{net}V

q=\frac{35}{12}\times 8=\frac{70}{3} \muf

As capacitors are in series so charge flow will be same in both capacitors

Voltage drop in 5 \muf capacitor

V=\frac{70}{3}\times \frac{1}{5}=\frac{14}{3} V\approx 4.67 V                              

8 0
3 years ago
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