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3 years ago

A 2.0 kg mass weighs 10 Newtons on planet X. what is the acceleration due to gravity on planet X? Show the work.

Physics

1 answer:

KengaRu [80]3 years ago

8 0

Answer: The gravitational acceleration on planet X is 5 N/kg

On Earth (with the gravitational accelartion g_E) the mass of 2kg will correspond to

$F_E = m\cdot g_E = 2.0 \mbox{kg}\cdot 9.8 \frac{N}{kg} = 19.6 N$

On planet X we are told the same measure is only 10N. Since there is a proportional relationship between g and F, we can calculate g_X:

$\frac{F_E}{g_E}=\frac{F_X}{g_X} \implies\\g_x = \frac{g_E\cdot F_X}{F_E}=\frac{9.8 N/kg \cdot 10 N }{19.6N}=5 \frac{N}{kg}$

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Which of the following scenerios fits all of the criteria for the two-source interference equations to be valid?

vekshin1

Answer:

answer the correct is B

Explanation:

For the interference phenomenon to occur, some conditions must be met.

* You must have a light in phase and coherent, for this you can for a light from an incandescent source through a single slit, the light that comes out is coherent

* This light must strike two slits

* the light that passes through the slits must hit a distant screen and be able to see the phenomenon of constructive interference

when examining the different answer the correct one is B

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3 years ago

Jake drags a sled of mass 18 kg across the snow. The sled is attached to a rope that he pulls with a force of 70 N at an angle o

Advocard [28]

If the 30 N on the rope were pulled straight up, it would offset the force of gravity ( m g = 10 kg * 9.8 N/kg = 98 N) , leaving a net force up from the ground on the sled of 98-30 = 68 N. Since the rope is pulled at the angle of 25o, only part of the force is in the upward direction, (30N)(sin(25) = (30)(.423) = 12.7. So the net force becomes 98 N down offset by 12.7 up or 98-12.7 = 85.3 N. Ah, there it is: C.

8 0

3 years ago

Read 2 more answers

A man is 40 kg . calculate his weight.(g=10m/s^2)

Dafna1 [17]

${ \large{ \bf{Weight = mg}}}$

${ \large{ \bf{Mass = 40 \: kg \: \: \: \: (given)}}}$

${ \large{ \bf{Weight = 40 \times 10}}}$

${ \large{ \therefore{ \bf{ \red{ Weight = 400N}}}}}$

5 0

3 years ago

The frequency of a person's pendulum is 0.3204 Hz when at a location where g is known to be exactly 9.800 m/s^2.

wel

Answer:

A) g = 9.751 m/s², B) h = 2.573 10⁴ m

Explanation:

The angular velocity of a pendulum is

w = √ g / L

Angular velocity and frequency are related.

w = 2π f

f = 1 / 2π √ g / L

A) with the initial data we can look for the pendulum length

L = 1 /4π² g / f²

L = 1 /4π² 9,800 / 0.3204²

L = 2.4181 m

The length of the pendulum does not change, let's look for the value of g for the new location

g = 4π² f² L

g = 4π² 0.3196² 2.4181

g = 9.75096 m / s²

g = 9.751 m/s²

B) The value of the acceleration of gravity can be found with the law of universal gravitation

F = G m M / $R_{e}$ ²

And Newton's second law

W = m g

W = F

G m M / $R_{e}$ ² = mg

g = G M / $R_{e}$ ²

$R_{e}$ ² = G M / g

Let's calculate

$R_{e}$ ² = 6.67 10⁻¹¹ 5.98 10²⁴ /9.75096

R = √ 4.0905 10¹³ = √ 40.9053 10¹²

R = 6.395726 10⁶ m

The height above sea level is

h = R - [tex]R_{e}[/tex

h = (6.395726 -6.37) 10⁶

h = 0.0257256 106

h = 2.573 10⁴ m

7 0

3 years ago

An object weighs 15N in air and 13N when completely

anastassius [24]

Answer:

The volume of water displaced = 0.204 m³

Explanation:

From Archimedes' principle,

Upthrust = lost in weight = weight of water displaced.

U = W₁ - W₂..................... Equation 1

Where U = upthrust, W₁ = weight in air, W₂ = weight when completely submerged in water.

Given: W₁ = 15 N, W₂ = 13 N

Substituting these values into equation 1

U = 15 - 13

U = 2 N

But,

Weight of water displaced = mass of water displaced. × acceleration due to gravity.

Mass of water displaced = weight of water displaced/ acceleration due to gravity.................... Equation 2

Where: acceleration due to gravity = 9.8 m/s², weight of water displaced = 2 N

Substituting these values into equation 2

Mass of water displaced = 2/9.8

Mass of water displaced = 0.204 kg.

Also,

Volume of water displaced = mass of water displaced/ Density of water.............. Equation 3

Where Density of water = 1.0 kg/m³, mass of water displaced = 0.204 kg

Substituting these values into equation 3 above,

Volume of water displaced = 0.204/1

volume of water displaced = 0.204 m³

Therefore the volume of water displaced = 0.204 m³

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3 years ago