The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun
        
             
        
        
        
Answer:
(A) Consists of a small number of tiny particles that are far apart- relative in their size.
Explanation:
An <em>ideal gas</em> is defined as a simplification of a real gas, with punctual particles, in which all collisions are elastic, with random displacements and with no attractive force between them. 
 
The assumption of the particles being punctual make clear that they do not have size at all. So if they were far apart-relative in their size, they can not collide each other, that is why assumption (B) can not be possible (<u><em>for that particular case</em></u>). 
It is clear that (A) is not an assumption for an ideal gas, because do not fit in any of its properties.
Elastic collision: It is a case in which the energy is conserved (Kinetic Energy).
Kinetic Energy: It is the energy that will have an object as a consequence of its movement. 
 
        
             
        
        
        
Answer:
r₂ = 0.2 m
Explanation:
given,
distance = 20 m
sound of average whisper = 30 dB
distance moved closer = ?
new frequency = 80 dB
using formula
 
    I₀ = 10⁻¹² W/m²
now,
 
 
 
to hear the whisper sound = 80 dB
 
 
 
we know intensity of sound is inversely proportional to square of distances
 
 
 
   r₂ = 0.2 m
 
        
             
        
        
        
Answer:
F=m(11.8m/s²)
For example, if m=10,000kg, F=118,000N.
Explanation:
There are only two vertical forces acting on the rocket: the force applied from its thrusters F, and its weight mg. So, we can write the equation of motion of the rocket as:

Solving for the force F, we obtain that:

Since we know the values for a (2m/s²) and g (9.8m/s²), we have that:

From this relationship, we can calculate some possible values for F and m. For example, if m=10,000kg, we can obtain F:

In this case, the force from the rocket's thrusters is equal to 118,000N. 
 
        
             
        
        
        
Answer:
 x = 6.94 m
Explanation:
For this exercise we can find the speed at the bottom of the ramp using energy conservation
Starting point. Higher
             Em₀ = K + U = ½ m v₀² + m g h
Final point. Lower
              = K = ½ m v²
 = K = ½ m v²
             Em₀ = Em_{f}
             ½ m v₀² + m g h = ½ m v²
             v² = v₀² + 2 g h
              
Let's calculate
              v = √(1.23² + 2 9.8 1.69)
              v = 5.89 m / s
In the horizontal part we can use the relationship between work and the variation of kinetic energy
             W = ΔK
             -fr x = 0- ½ m v²  
                
Newton's second law
               N- W = 0
      
The equation for the friction is
                fr = μ N
                fr = μ m g
We replace
              μ m g x = ½ m v²
              x = v² / 2μ g
Let's calculate
             x = 5.89² / (2 0.255 9.8)
             x = 6.94 m