If the mass of the object and the volume of the object is determined;
Then, the density of the object is determined by taking the ratio of the mass and volume.
<h3>What is density of an object?</h3>
The density of an object is the ratio of the mass and volume of that object.
Mathematically;
To determine the density of an object therefore, the physical characteristics of mass and the volume of the object are measured.
The mass of the object is obtained using a scale or a balance.
The volume of the object if a solid is obtained using a displacement bottle. If it is a liquid, a measuring cylinder is used.
The density of the object is then obtained by taking the ratio of the mass and the volume of the object.
In conclusion, the density of an object is determined from the volume and mass ratio.
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The total momentum of the players after collision is 130 kgm/s.
The given parameters:
- <em>Initial momentum of the returner, </em>
<em> = 0 kgm/s</em> - <em>The initial momentum of the diving player, </em>
<em> = 130 kgm/s</em>
The total momentum of the players after collision is determined by applying the principle of conservation of linear momentum as follows;
Thus, the total momentum of the players after collision is 130 kgm/s.
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The current in the 50 Ω resistor is A) 1.2 A
Answer:
Energy of Photon = 4.091 MeV
Explanation:
From the conservation of energy principle, we know that total energy of the system must remain conserved. So, the energy or particles before collision must be equal to the energy of photons after collision.
K.E OF electron + Rest Energy of electron + K.E of positron + Rest Energy of positron = 2(Energy of Photon)
where,
K.E OF electron = 3.58 MeV
Rest Energy of electron = 0.511 MeV
Rest Energy of positron = 0.511 MeV
K.E OF positron = 3.58 MeV
Energy of Photon = ?
Therefore,
3.58 MeV + 0.511 MeV + 3.58 MeV + 0.511 MeV = 2(Energy of Photon)
Energy of Photon = 8.182 MeV/2
<u>Energy of Photon = 4.091 MeV</u>
