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Kipish [7]
3 years ago
12

What are some indicators of energy transformations?

Physics
1 answer:
Annette [7]3 years ago
5 0

Explanation:

Contact, vision, sound, flavor, and smell are all markers of energy transformations. The most basic example would be when we notice something has begun to pass through vision. Whenever an entity accelerates or slows down, energy is constantly transformed.

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For how long a time must a tow truck pull with a force of 550N on a stalled 1200kg car to give it a forward velocity of 2.0m/s?
horsena [70]

Answer:

4.36 seconds

Explanation:

According to the question;

  • Force is 550 N
  • Mass of the car is 1200 kg
  • Velocity of the car is 2.0 m/s

We are needed to find the time the car must the tow track pull the car.

  • From Newton's second law of motion;
  • Impulsive force, F = Mv÷t , where m is the mass, v is the velocity and t is the time.

Rearranging the formula;

t = mv ÷ F

Thus;

Time = (1200 kg × 2.0 m/s²) ÷ 550 N

        = 4.36 seconds

Thus, the time needed to pull the car is 4.36 seconds

5 0
3 years ago
Where on the table would a group’s ionization energy be the greatest?
ANEK [815]

Explanation:

The first ionization energy varies in a predictable way across the periodic table. The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest first ionization energy, while francium has one of the lowest.

6 0
4 years ago
The topsoil layer has the greatest concentration of organic matter. The subsoil generally lacks organic matter, but it does rece
zmey [24]

Answer:

C. the C horizon likely has a rockier texture than the topsoil and subsoil.

Explanation:

because i did it on study island

3 0
3 years ago
A large ant is standing on the middle of a circus tightrope that is stretched with tension T_s. The rope has mass per unit lengt
k0ka [10]

Answer:

A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}

Explanation:

As we know that the speed of the wave in string is given as

v = \sqrt{\frac{T_s}{\mu}}

now we will have

frequency of the wave is given as

f = \frac{v}{\lambda}

f = \frac{1}{\lambda}\sqrt{\frac{T_s}{\mu}}

now if the ant will feel weightlessness then we will have

mg = m\omega^2 A

so we will have

A = \frac{g}{\omega^2}

A = \frac{g}{4\pi^2 f^2}

A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}

3 0
4 years ago
The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of
Oksi-84 [34.3K]

Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Explanation: To find the answer, we need to know about the different equations of planetary motion.

<h3>How to find the initial speed of the rock as it left the astronaut's hand?</h3>
  • We have the expression for the initial velocity as,

                           v=\sqrt{2gh}

  • Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,

                       g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132

  • Now, the velocity will become,

                        v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s

<h3>How to find the speed of the satellite?</h3>
  • As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,

                       v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s

Thus, we can conclude that,

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Learn more about the equations of planetary motion here:

brainly.com/question/28108487

#SPJ4

3 0
2 years ago
Read 2 more answers
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