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3 years ago

What are some indicators of energy transformations?

Physics

1 answer:

Annette [7]3 years ago

5 0

Explanation:

Contact, vision, sound, flavor, and smell are all markers of energy transformations. The most basic example would be when we notice something has begun to pass through vision. Whenever an entity accelerates or slows down, energy is constantly transformed.

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Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet

amid [387]

Responder:

18.75 atmósferas

Explicación:

Paso uno:

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

<em><u>La presión final es de 18.75 atm.</u></em>

5 0

3 years ago

Geronimo wants to move an object 12 meters. Calculate the net work done by the object with an applied force of 150 N and a frict

valina [46]

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

4 0

3 years ago

State three ways in which a machines are useful to us.

olga2289 [7]

1: a machine makes our work easier

2: a machine can help us find important information

3: a machine can help us transport from a place to another

3 0

3 years ago

1) Subatomic particles called muons can be created in the upper atmosphere by collisions of cosmic rays (energetic particles com

Vsevolod [243]

Answer and explanation:

Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)

In muon rest frame it travels Zero meters

Distance, d = Velocity, v * Time, s

$where, v = 0.9c = 0.9 \times 8 \times 10^8 , s = 2.2 \mu s$

$d = 0.9 \times 3 \times 10^8 \times 2.2 \times 10^{-6}\\\\d = 594m$

Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame

that is same as in part C which is 594m

Using lorentz contraction

In the rest frame of someone standing on the mountain

the distance is given by

$d' = \frac{d}{\gamma} = d\sqrt{1 - \frac{v^2}{c^2}}, where, \frac{1}{\gamma}= \sqrt{1 - \frac{v^2}{c^2}}$

$d' = 594\sqrt{1 - \frac{(0.9c)^2}{c^2}}$

$d' = 594\sqrt{1 - 0.81}$

$d' = 594 \times 0.4359$

d' = 258.92m

in the rest frame of someone standing on the mountain,

muon moves straight down

3 0

4 years ago

Two trains approach each other on parallel tracks. Each has a speed of 95 kph relative to the ground. If they are initially 8.5

aliya0001 [1]

Answer: 2.83 minutes

Explanation:

It is understood that trains are approaching. That is, they have speeds of equal magnitude but opposite. When train A travels x meters northbound, then train B travels the same distance southbound.

Therefore trains approach at a speed of:

$V = 95 +95 = 190\ km / h$