All categories

3 years ago

What are some indicators of energy transformations?

Physics

1 answer:

Annette [7]3 years ago

5 0

Explanation:

Contact, vision, sound, flavor, and smell are all markers of energy transformations. The most basic example would be when we notice something has begun to pass through vision. Whenever an entity accelerates or slows down, energy is constantly transformed.

You might be interested in

For a medium to transmit a wave, the medium must _____.

Paul [167]

I think the answer is D. permit the wave to travel through it

8 0

3 years ago

Consider a car that travels between points A and B. The car's average speed can be greater than the magnitude of its average vel

omeli [17]

Answer:

Explanation:

True

Average speed is the ratio of total distance traveled to the total time taken and average velocity is total displacement to the total time.

And we know distance is either equal to or greater than displacement so we can say that for equal time interval magnitude of average velocity can never be greater than average speed.

7 0

3 years ago

A classic demonstration illustrating eddy currents is performed by dropping a permanent magnet inside a conducting cylinder. The

kvv77 [185]

Answer:

The correct solution is "0.69 N".

Explanation:

The given values are:

Mass of magnet,

m = 70 g

or,

= 0.07 kg

Width,

= 1.0 cm

Velocity,

= 10 cm/s

Length of the pipe,

= 80 cm

Whenever the velocity is constant, then the net force which is acting on the magnet will be "0".

On the magnet,

The up-ward force will be:

⇒ $F=mg$

On substituting the values, we get

⇒ $=0.07\times 9.8$

⇒ $=0.69 \ N$

4 0

3 years ago

A ball is projected at an angle of 53º. If the initial velocity is 48 meters/second, what is the vertical component of the veloc

solong [7]

Answer: B

Explanation:

The vertical component of a vector such as velocity is the magnitude of the vector multiplied by the sine of the angle.

$V_y=48*sin(53)=38.3m/s$

5 0

3 years ago

A 0.20-kg particle moves along the x axis under the influence of a conservative force. The potential energy is given by

anastassius [24]

Answer:

e) 11 m/s

Explanation:

For a particle under the action of a conservative force, its mechanical energy at point 0 is must be equal to its mechanical energy at point 1:

$K_1+U_1=K_0+U_0\\\\\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(x_1)^2+(2.0\frac{J}{m^4})(x_1)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})(x_0)^2+(2.0\frac{J}{m^4})(x_0)^4]$

In $x_1=1.0m$ the speed is given, so $v_1=5.0\frac{m}{s}$ and $x_0=0$ . Replacing:

$\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(1m)^2+(2.0\frac{J}{m^4})(1m)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})0^2+(2.0\frac{J}{m^4})(0)^4]\\\frac{mv_1^2}{2}+8.0J+2.0J=\frac{mv_0^2}{2}\\\frac{mv_0^2}{2}=\frac{mv_1^2}{2}+10J\\v_0=\sqrt{\frac{2}{m}(\frac{mv_1^2}{2}+10J)}\\v_0=\sqrt{\frac{2}{0.2kg}(\frac{(0.2kg)(5\frac{m}{s})^2}{2}+10J)}\\v_0=11.18\frac{m}{s}$

7 0

4 years ago