All categories

3 years ago

Why are the densities of corn syrup and gasoline expressed as a range of values?

Chemistry

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

The answer is because they are not a substance, but a mixture of organic compounds.

Explanation:

A range of values is used because they are not a substance, but a mixture of organic compounds that has a range of molar masses. Corn syrup contains glucose in not less than 70% by weight of total solids and a reducing sugar content of 20% by weight on a dry basis. The composition of gasoline depends on the source from which it is extracted, therefore it has different molar masses. A gasoline with a long carbon chain is heavy and has a higher mass for a fixed volume, so its density will increase. Any change affecting the product will lead to an increase or decrease in density.

Have a nice day!

Maslowich3 years ago

4 0

A range of values is given for the density of gasoline and corn syrup could be because these substances changes their volumes along with the changes in temperature which will result to a change in density as well. Hope this answers the question.

You might be interested in

In some developing nations, the percentage of animal protein from fish in the diet can be as high as _____.

Makovka662 [10]

Answer:

20%

Explanation:

The fish consumption has had lot of variations in the past few centuries, most noticeably in the last century. Initially it was the richer countries that had population which was consuming the most animal protein from fish in the world, while the developing nations had less. Things have changed though, especially during the 1990's, when the developing nations experienced a rapid increase in the consumption of fish. This was largely due to the growing standard and the availability of fish, so in some of the developing nations the percentage of animal protein from fish reached around 20%.

5 0

3 years ago

What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7

mariarad [96]

The empirical formula of hydrocarbon is CH2

The molecular formula of the hydrocarbon is C6H12

<u><em>Explanation</em></u>

Hydrocarbon is made up of carbon and hydrogen

<h3><u><em> </em></u>Empirical formula calculation</h3>

Step 1: find the moles CO2 and H2O

moles =mass/molar mass

moles of CO2 = 6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol = 0.15 moles

Step 2: Find the moles ratio of Co2:H2O by diving each mole by smallest mole(0.15)

that is for CO2 = 0.15/0.15 =1

For H2O = 0.15/0.15 =1

therefore the mole ratio of Co2 : H2O = 1:1 which implies that 1 mole of Co2 and 1 mole of H2O is formed during combustion reaction.

From the the law of mass conservation the number of atoms in reactant side must be equal to number of atoms in product side

therefore since there 1 atom of C in product side there must be 1 atom of C in reactant side.

In addition there is 2 H atom in product side which should be the same in reactant side.

From information above the empirical formula is therefore = CH2

Molecular formula calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n = 84 g/mol

n = 6

multiply the each subscript in CH2 by 6

Therefore the molecular formula = C6H12

5 0

3 years ago

The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p

earnstyle [38]

Answer:

The frequency is $f = 2,01 * 10^{15} \ Hz$

Explanation:

From the question we are told that

The energy required to ionize boron is $E_b = 801 KJ/mol$

Generally the ionization energy of boron pre atom is mathematically represented as

$E_a = \frac{E_b}{N_A}$

Here $N_A$ is the Avogadro's constant with value $N_A = 6.022*10^{23}$

$E_a = \frac{801}{6.022*10^{23}}$

=> $E_a = 1.330 *10^{-18} \ J/atom$

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

$E = hf = E_a$