How many atoms of oxygen (o)are present 2naOH+H2SO4 2H2O+Na2SO4

Based on the results you observed for the iodine test and Benedict’s test, is it better to detect enzyme activity by measuring t

dlinn [17]

Answer:

Is better use the Benedict's test by the increase in the amount of the products if the enzyme is a reductase

Explanation:

The Benedict's test works by the reaction of the reducing sugars with the ion cupric of the reactive. If the enzyme is a reductase (degrades polysaccharides into bi o monosaccharides), it should cut the polysaccharide bond and the products would react with the Benedict's cupric ion

I hope you undestand me

3 0

3 years ago

A gaseous compound is 30.4 % N and 69.6% OF. A 5.25 g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 958

Harman [31]

Answer:

The molecular formula = N2O4

Explanation:

Step 1: Data given

A gaseous compound is 30.4 % N and 69.6%

Mass of the compound = 5.25 grams

Volume of the gas = 1.00 L

Pressure of the gas = 958 mmHg = 1.26 atm

Temperature of the gas = -4 °C = 273 -4°C = 269 Kelvin

Molar mass of N = 14 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate mass of N

Mass of Nitrogen = 5.25 grams * 0.304 = 1.596 grams

Step 3: Calculate mass of O

Mass of Oxygen = 5.25 grams * 0.696 = 3.654 grams

Step 4: Calculate number of moles N

Number of moles N = Mass of N/ Molar mass of N

Moles of N = 1.596 grams / 14g/mol

Moles of N = 0.114 moles N

Step 5: Calculate moles of O

Moles O = 3.654 grams / 16 g/mol

Moles 0 = 0.2884 moles

Step 6: Calculate empirical formule

We calculate the empirical formule by dividing number of moles by the smallest number of mol

N : 0.114 / 0.114 = 1

O: 0.2284 / 0.114 = 2

Empirical formule = NO2

Step 7: Calculate number of moles of 5.25 g sample via gas law:

p*V = nRT

⇒ with p = the pressure = 1.26 atm

⇒ with v = 1.00 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/ K*mol

⇒ with T = the temperature = 269 K

number of moles n = (p*V)/(R*T)

n = (1.26*1L)/(0.08206*269)

n = 0.057 mol

Step 8: Calculate molar mass of the compound

This means 5.25 grams of the gas = 0.057 moles

So 1 mol of the compound has a molar mass of: 5.25 / 0.057 = 92.11 g/mol

Step 9: Calculate molar mass of the empirical formula NO2

N = 14 g/mol

O = 16 g/mol

NO2 = 14 + 16 + 16 = 46 g/mol

The empirical formule NO2 has a molar mass of 46 g/mol

Step 10: Calculate molecular formula

92.11 / 46 = 2

This means the empirical formula should be multiplied by 2

2*(NO2) = N2O4

The molecular formula = N2O4

8 0

3 years ago

PLEASE HELP IM REALLY STRESSED OUT AND I JUST NEED SOMEONE TO DO THIS FOR ME! IK ITS ALOT SORRY! In this task, you'll determine

Burka [1]

Answer:

The reaction is endothermic

Part A: Yes because there is an immediate reaction of bubbling vigorously.

Part B: It releases energy because when the compounds are added together they are immediately releasing it by bubbling and turning cold.

Part C: Yes because the liquids inside when combined give off coldness that makes the liquid temperature decrease to use this chemical reaction could definitely be used to keep something cold

Explanation:

7 0

3 years ago

Binomial nomenclature example and sentence using that word please help im going to cry

Alexandra [31]

What’s wrong? ...........:.........

4 0

2 years ago

What is the mass in grams of 120 liters at STP oh He gas

skad [1K]

The mass of He gas = 21.428 g

<h3>Further explanation</h3>

Given

120 liters of He gas

Required

the mass in grams

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

Mol for 120 L :

$\tt \dfrac{120}{22.4}=5.357~moles$

Mass of He gas(MW=4 g/mol) :

$\tt mass=mol\times Ar\\\\mass=5.357\times 4=21.428~g$

5 0

2 years ago