Based on the ideal gas relation:
PV = nRT
where P = pressure ; V = volume ; T = temperature
n = number of moles; R = gas constant = 0.0821 L atm/mol-K
Step 1: Find the number of moles of O2
n = PV/RT = 1 * 3.90/0.0821*273 = 0.1740 moles
Step 2: Calculate the molecules of O2
Now, 1 mole of O2 corresponds to 6.023 * 10²³ molecules of O2
Therefore, 0.1740 moles of O2 corresponds to-
0.1740 moles of O2 * 6.023*10²³ molecules of O2/1 mole of O2
= 1.048 * 10²³ molecules of O2
Elements 3 to 10 (Li to Ne) show a more or less steady increase in ionization energy.
<h3>What is ionisation energy?</h3>
The amount of energy required to remove an electron from an isolated atom or molecule.
The major difference is the increasing number of protons in the nucleus as you go from lithium to neon. That causes greater attraction between the nucleus and the electrons and so increases the ionization energies. In fact the increasing nuclear charge also drags the outer electrons in closer to the nucleus.
Learn more about the ionisation energy here:
brainly.com/question/20658080
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<span>Heat would make the molecules move faster so they would spread out therefore making air less dense.
Less dense means less packed. Heat increase the kinetic energy</span>
Answer: 5.4
Explanation:
P2 = P1V1/V2
P2 = (.60atm x 27L) / 3.0L = 5.4atm
Answer:
the answer is option E they are bronsted lowry acid
