How many 5 cm squares

Suppose a photon with an energy of 1.60 eV strikes a piece of metal. If the electron that it hits loses 0.800 eV leaving the met

JulsSmile [24]

To solve this problem it is necessary to apply the concepts related to the change of Energy in photons and the conservation of energy.

From the theory we could consider that the energy change is subject to

$\Delta E = E_0 -W_f$

Where

$E_0 =$ Initial Energy

$W_f =$ Energy loses

Replacing we have that

$\Delta E = 1.6-0.8$

$\Delta E = 0.8eV$

Therefore the Kinetic energy of the electron once it has broken free of the metal surface is 0.8eV

7 0

3 years ago

Two stationary positive point charges, charge 1 of magnitude 3.05 nC and charge 2 of magnitude 1.85 nC, are separated by a dista

luda_lava [24]

To solve this problem we will apply the concepts related to voltage as a dependent expression of the distance of the bodies, the Coulomb constant and the load of the bodies. In turn, we will apply the concepts related to energy conservation for which we can find the speed of this

$V = \frac{kq}{r}$

Here,

k = Coulomb's constant

q = Charge

r = Distance to the center point between the charge

From each object the potential will be

$V_1 = \frac{kq_1}{r_1}+\frac{kq_2}{r_2}$

Replacing the values we have that

$V_1 = \frac{(9*10^9)(3.05*10^{-9})}{0.41/2}+\frac{(9*10^9)(1.85*10^{-9})}{0.41/2}$

$V_1 = 215.12V$

Now the potential two is when there is a difference at the distance of 0.1 from the second charge and the first charge is 0.1 from the other charge, then,

$V_1 = \frac{(9*10^9)(3.05*10^{-9})}{0.1}+\frac{(9*10^9)(1.85*10^{-9})}{0.41-0.1}$

$V_2 = 328.2V$

Applying the energy conservation equations we will have that the kinetic energy is equal to the electric energy, that is to say

$\frac{1}{2} mv^2 = q(V_2-V_1)$

Here

m = mass

v = Velocity

q = Charge

V = Voltage

Rearranging to find the velocity

$v = \sqrt{ \frac{2q(V_2-V_1)}{m}}$

Replacing,

$v = \sqrt{ \frac{-2(1.6*10^{-19})(328.2-215.12)}{9.11*10^{-3}}}$

$v = 6.3*10^6m/s$

Therefore the speed final velocity of the electron when it is 10.0 cm from charge 1 is $6.3*10^6m/s$

6 0

3 years ago

My kitty just past her name was winter :c

Yuliya22 [10]

Oh I’m so sorry rip winter

7 0

3 years ago

Read 2 more answers

How do the densities of the jovian and terrestrial planets compare?

timofeeve [1]

Hello

The jovian density is $1.33~g/cm^3$ , while the density of terrestrial planets is much higher. For instance, the earth's density is $5.51~g/cm^3$ . The reason of this difference is in the different chemical composition: while jupiter is made of gas (mainly hydrogen), with lower density, while the terrestrial planets are made of solid and liquid, with compounds of higher density.

5 0

3 years ago

Planets in the solar system revolve around the Sun in an orbital path and can vary from rocky and terrestrial objects to gaseous

Yuliya22 [10]

Answer:

Gaseous; liquid.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Some examples of the planet are Mars, Venus, Earth, Mercury, Neptune, Jupiter, Saturn, Uranus, Pluto, etc.

Basically, the planets are divided into two (2) main categories and these includes;

I. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

II. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

In conclusion, Planets in the solar system can vary from rocky and terrestrial objects to gaseous and liquid object.

However, the set of characteristics which is unique to the outer planets are gaseous and liquid.

3 0

3 years ago