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3 years ago

Which of the following hypotheses is both falsifiable and testable?

2 answers:

5 0

B. If all plants are watered at least once a day then they will all grow at least 1 cm a day.

All plants grow at different rates.

Hope this helps! XD

Vladimir [108]3 years ago

5 0

Answer:

The correct answer to the question: Which of the following hypotheses is both falsifiable and testable:____, would be, B: If all plants are watered at least once a day then they will all grow at least 1 cm a day.

Explanation:

In order to carry out research, hypothesis must be generated that will ask the questions necessary to find out information on different topics. However, not all questions, or statements will serve as a source for research, or lead to research. For this to happen, a researched must know that there are conditions to how to formulate a hypothesis; the first condition is that the hypothesis must be verifiable, or testable, which means, it can be proven. The second is, that the hypothesis must be falsifiable, or refutable, by research, and the third, the hypothesis must lead to results that can lead to further testing and reproduction. In this case, saying that all plants, when watered once a day at least, will grow a minimum of 1 cm a day cannot be used because it is based on a wrong assumption, given that all plants grow at different rates, and not all can be watered in the same way. This, in itself, from the outset, invalidates the hypothesis.

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Suppose the initial kinetic energy and final potential energy in an experiment are both zero. What can you conclude?

puteri [66]

Answer:

That an item is neither moving nor staying still in a position that is building up energy.

Explanation:

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4 years ago

Read 2 more answers

A ball is thrown horizontally from the top of a building 14.9 m high. The ball strikes the ground at a point 107 m from the base

umka2103 [35]

Answer:

1) t=1.743 sec

2)Vo=61.388 m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the initial velocity of the ball that is=61.388 m/sec

4)Vf=17.08 m/s

Explanation:

1)From second equation of motion we get

h=Vit+(1/2)gt^2

here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion

14.9=(0)*t+(1/2)(9.8)t^2

t^2=14.9/4.9

t^2=3.040 sec

t=1.743 sec

2) s=Vo*t

Putting values we get

107=Vo*1.743

Vo=61.388 m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the initial velocity of the ball that is=61.388 m/sec

4)From third equation of motion we know that

Vf^2-Vi^2=2gh

here Vi=0 m/s,h=14.9 m

Vf^2=Vi^2+2gh=0+2(9.8)(14.9)

Vf^2=292.04

Vf=17.08 m/s

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3 years ago

What is the acceleration of a car going 50 mph that slows down to rest over 10 seconds?

VladimirAG [237]

Answer:

If the velocity is constant, then there is no acceleration. That is, the value of the acceleration is 0.

Explanation:

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3 years ago

A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump this hi

LUCKY_DIMON [66]

Answer:84.672 joules.

Explanation:

1) Data:

m = 7.2 kg
h = 1.2 m
g = 9.8 m / s²

2) Physical principle

Using the law of mechanical energy conservation principle, you have that the kinetic energy of the dog, when it jumps, must be equal to the final gravitational potential energy.

3) Calculations:

The gravitational potential energy, PE, is equal to m × g × h

So, PE = m × g × h = 7.2 kg × 9.8 m/s² × 1.2 m = 84.672 joules.

And that is the kinetic energy that the dog needs.

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4 years ago

two porters are available to carry a long timber wood.out of them one is weak.how to do you make less load to the weak one? writ

marshall27 [118]

Answer:

Please find the answer in the explanation.

Explanation:

Given that two porters are available to carry a long timber wood.out of them one is weak. how do you make less load to the weak one?

We can make the weak one to carry less load through two different ways or means.

First, if we can locate the centre of gravity and centre of mass of the long timbre wood, the week one can carry the other end away from the center of gravity and centre of mass.

Second, the strong porter can carry the long timbre wood almost to the fulcrum and allow the weak one to support at the other end. By doing this, the weak one will only carry light portion of the load.

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3 years ago