Answer:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
Explanation:
CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄
To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:
In solution, CuSO₄ and KOH will dissociate as follow:
CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)
KOH (aq) —> K⁺ (aq) + OH¯(aq)
CuSO₄(aq) + KOH (aq) —>
Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)
Note: Cu(OH)₂ is insoluble in water.
Therefore, the elemental equation is:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
Answer:
3. Sice increases, Ssw decreases, Ssys increases
Explanation:
Entropy basically refers to the degree of disorderliness of a system.
Ice Cube --> As the ice cube melts, it undergoes a change in state of matter from solid to liquid hence it's entropy increases as the degree of movement of its molecules is more disordered in the liquid state.
This means the likely options are; 1, 3 and 4.
Sidewalk --> The entropy here decreases as the ice melts on the side walk. This is because there is a reduction in temperature. Entropy is directly proportional to temperature. Decrease in temperature leads to decrease in entropy.
This means the likely option is 1 and 3
The net entropy change of the system is however positive.
No that is why I am asking for help
Animals with larger weights compensate for the large force they exert on the ground, by having a large footprint area in order to reduce the pressure of their feet on the ground.
<h3>Why do animals with large weight have large feet?</h3>
Large animals such as elephants, lions, hippopotamus, etc, usually have a large foot print area compared to smaller animals.
This larger footprint area helps to support their weight.
The weight of these animals exerts a force as well as pressure on the ground.
Pressure, force and area are related by the equation below:
The larger the area, the smaller the pressure.
In order to compensate for the large force they exert on the ground, larger animals possess a large footprint area in order to reduce the pressure of their feet on the ground.
Learn more about force, pressure and area at: brainly.com/question/8033367
We can use combined gas law,
PV/T = k (constant)
Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.
For two situations, we can use that as,
P₁V₁/T₁= P₂V₂/T₂
P₁ = 795 mm Hg
V₁ = 642 mL
T₁ = (273 + 23.5) K = 296.5 K
P₂ = ?
V₂ = 957 mL
T₂ = (273 + 31.7) K = 304.7 K
From substitution,
795 mm Hg x 642 mL / 296.5 K = P₂ x 957 mL / 304.7 K
P₂ = 548.072 mm Hg
760 mmHg = 1 atm
548.072 mm Hg = 1 atm x (548.072 mmHg / 760 mmHg)
= 0.721 atm
Pressure of Oxygen gas is 0.721 atm.
Answer is "A"
Here, we made an assumption that oxygen gas has an ideal gas behavior.
