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NISA [10]
3 years ago
11

Please Help with this ASAP: A wave vibrates 45 times in 30 seconds, calculate its frequency

Physics
2 answers:
JulijaS [17]3 years ago
4 0
Th answer would be 1.5
11111nata11111 [884]3 years ago
3 0
It’s gonna be 45/30 which is equal to 9/6=1.5
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A 2.1 times 103 - kg car starts from rest at the top of a 5.0 - m - long driveway that is inclined at 20 deg with the horizontal
VLD [36.1K]

Answer:

speed of the car at the bottom of the driveway is 3.8 m/s

Explanation:

given data

mass = 2.1× 10³ kg

distance = 5 m

angle = 20 degree

average friction force = 4 × 10³ N

to find out

find the speed of the car at the bottom of the driveway

solution

we find acceleration a by  force equation that is

force = mg×sin20 - friction force

ma = mg×sin20 - friction force

put here value

2100a = 2100 ( 9.8)×sin20 - 4000

a = 1.447 m/s²

so from motion of equation

v²-u² = 2as

here u is 0 by initial speed and v is velocity and a is acceleration and s is distance

v²-0 = 2(1.447)(5)

v = 3.8

speed of the car at the bottom of the driveway is 3.8 m/s

4 0
3 years ago
A tube with sealed ends has some sand at one end. When the tube is turned upside down the sand falls 0.6m then settles down agai
barxatty [35]

Answer:

2.943 J

Explanation:

Data:

acceleration due to gravity, g = 9.81 m/s²

mass of sand  = 0.5 kg

distance  = 0.6

Thermal energy  = the energy possessed by the falling sand

The force of sand = ma

                              = 0.5 * 9.81\\= 4.905 N

However, the energy is given as the force multiplied by the distance, so

E =fd

   4.905 * 0.6\\= 2.943 J

Therefore, the thermal energy is 2.943 joules

 

4 0
2 years ago
Read 2 more answers
To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to
dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

y=ut+\frac{1}{2} gt^2

Where g=9.8 m/s^2

40=0+\frac{1}{2}(9.8)t^2=4.9t^2

t^2=\frac{40}{4.9}

t=\sqrt{\frac{40}{4.9}}=2.86 s

x=v_x\times t

30=v_x(2.86)

v=v_x=\frac{30}{2.86}=10.49 m/s

By work energy theorem

Change in kinetic energy=Work done= mgh-W

\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W

\frac{1}{2}(3)(10.49)^2-0=676.2-W

W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0
3 years ago
A 52-kg bike is moving along a smooth road at a constant velocity of 8.4 m/s. What is the net force acting on the bike
kirill [66]

Answer:

0 N

Explanation:

Net force = mass × acceleration

∑F = ma

The velocity is constant, so the acceleration is 0.  Therefore, the net force is 0.

3 0
3 years ago
Identify properties of a human body system
IceJOKER [234]

Answer:

integumentary, skeletal, muscular, nervous, endocrine, cardiovascular, lymphatic, respiratory, digestive, urinary, and reproductive

Explanation:

and this is biology not physics

5 0
2 years ago
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