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4 years ago

What does a refractive index from medium 1 to medium 2 mean? Isn't one of the medium must be vacuum?

Physics

1 answer:

Musya8 [376]4 years ago

6 0

Refractive index is the measure of bending of a ray of light when passing from one medium into another. It is not necessary that one medium must be vaccum.

For example, the image below shows refraction, where first medium is air and second medium is water.

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An eagle flies from its perch in a tree to the ground to capture and eat its prey. describe its energy transfromation

ddd [48]

10% energy is transferred from the prey to eagle and 90% energy is lost in the enviorment .

7 0

3 years ago

A 4kg box is pressed into a spring. The spring constant k=220N/m. The box is released at the bottom of a frictionless ramp and r

AVprozaik [17]

Answer:

Explanation:

The stored elastic energy in the spring helps the box to rise to a height of .75 m

So stored elastic energy = potential energy attained

1/2 k d² = mgh , k is spring constant , d is compression in spring , m is mass of box , h is height attained .

Putting the values

.5 x 220 x d² = 4 x 9.8 x .75

d² = .2673

d = .517 m

51.7 cm .

8 0

3 years ago

Read 2 more answers

A roller coaster has a 100.0 kg cart at the top of a 22.0 m ramp. As it goes down the ramp, it change 800.0 joules of energy to

AlekseyPX

Answer:

d.20760 J

Explanation:

We are given that

Mass of cart=m=100 kg

At the top,h=22 m

Amount of energy convert into heat due to friction=E=800 J

We have to find the kinetic energy at the bottom of the ramp.

Potential energy drop=mgh= $100\times 9.8\times 22=21560 J$

Kinetic energy at the bottom=Potential energy drop-energy lost due to friction

Kinetic energy at the bottom =(21560-800) J

Kinetic energy at the bottom=20760 J

Hence, the kinetic energy at the bottom of the ramp=20760 J

d.20760 J

5 0

3 years ago

The average intensity of the sunlight in Miami, Florida, is 1040 W/m2. What is the average value of the radiation pressure due t

iogann1982 [59]

Answer:

The average value of the radiation pressure due to this sunlight in Miami is 3.467 x 10⁻⁶ N/m²

Explanation:

Given;

the average intensity of the sunlight in Miami, I = 1040 W/m²

the average value of the radiation pressure = ?

Radiation pressure is calculated as;

$Radiation \ pressure = \frac{I *C_R}{C}$

Where;

I is the average intensity of the sunlight

CR is solar radiation coefficient = 1

C is the speed of light = 3 x 10⁸ m/s

$Radiation \ pressure = \frac{I *C_R}{C} \\\\Radiation \ pressure = \frac{1040 *1}{3*10^8} \\\\Radiation \ pressure = 3.467*10^{-6} \ N/m^2$

Therefore, the average value of the radiation pressure due to this sunlight in Miami is 3.467 x 10⁻⁶ N/m²

7 0

3 years ago

Calculate the wavelength of light emitted when each of the following n=5 n=3

denis-greek [22]

When it transmits from n=5 to n=3,
∧ = Rh [ni - nf]
∧ = Rh [1/3-1/5]
∧ = Rh 2/15

So, your final answer is Rh * 2/15
Where, Rh = Rydberg's constant

Hope this helps!

4 0

3 years ago