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seropon [69]
4 years ago
6

What does a refractive index from medium 1 to medium 2 mean? Isn't one of the medium must be vacuum?

Physics
1 answer:
Musya8 [376]4 years ago
6 0

Refractive index is the measure of bending of a ray of light when passing from one medium into another. It is not necessary that one medium must be vaccum.

For example, the image below shows refraction, where first medium is air and second medium is water.

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Calculate the work performed by an ideal Carnot engine as a cold brick warms from 150 K to the temperature of the environment, w
olga nikolaevna [1]

To solve this problem, apply the concepts related to the calculation of the work performed according to the temperature change (in an ideal Carnot cycle), for which you have to:

W = \int\limit_{T_c}^{T_H} C (1-\frac{T_H}{T})

Where,

C = Heat capacity of the Brick

T_C= Cold Temperature

T_H = Hot Temperature

Integrating,

W = C (T_H-T_C)- T_H C ln (\frac{T_H}{T_C})

Our values are given as

T_H= 300K

T_C = 150K

Replacing,

W = (1) (300-150)-300(1)ln(2)

W = 150-300ln2

W = -57.94kJ \approx 58kJ

Therefore the work perfomed by this ideal carnot engine is 58kJ

5 0
4 years ago
Someone help with this also
Mumz [18]
I’m pretty sure it’s average speed= total distance and total time which is A.
3 0
3 years ago
A car moving on a straight level road changes its speed from 3.5m/s to 4.5m/s in 5.00 seconds. Find it’s acceleration
mixer [17]

Answer:

0.2m/s2

Explanation:

acceleration= change in velocity ( in this case speed)/ change in time.

4.5-3.5=1m/s

change in time=5-0 =5

1m/s divided by 5 seconds acceleration as the result

8 0
3 years ago
The segment on the left has diameter 1.6 mm, and each of the segments on the right has diameter 0.4 mm. Assume the blood can be
oksian1 [2.3K]

Answer:

Explanation:

The flow entering the first segment will be the same as the flow exiting the second segment, and in both cases it will be equal to the velocity multiplied by the area of the segment. If Flow_{a} = Flow_{b} and Flow = VxA, then you have:

V_{a} x A_{a} = V_{b} x A_{b} (1)

You can also calculate the transversal area of each segment, because blood vessels are cylinders and you know each segment's diameter. The formula to calculate this is:

A = \pi /4 x d^{2}

Replacing d for each segment you have:

Area_{a} = 2.01 mmArea_{b} = 0.13 mm

Now, replacing these values on (1), you have:

V_{a} x 2.01 mm = V_{b} x 0.13 mm

(V_{a} x 2.01 mm)/0.13 mm = V_{b}

15.4 x V_{a} = V_{b}

This means that velocity in the second segment is 15.4 times the velocity in which blood entered the first segment.

5 0
3 years ago
A weight trainer lifts a 90.0-kg barbell from a stand 0.90 m high and raises it to a height of 1.75 m. What is the increase in t
nirvana33 [79]

Answer:

∆PE = 749.7 J

At 0.9 m high, PE = 793.8 J

At 1.75 m high, PE = 1543.5 J

7 0
2 years ago
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