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Stels [109]
3 years ago
12

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:

Chemistry
1 answer:
MAVERICK [17]3 years ago
8 0

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

[Ar]3d^1

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

[Ar]3d^6

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

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A gas occupies a volume of 2.4 L at 14.1 kPa. What volume will the gas occupy at 84.6 kPa?
Naddik [55]

Answer:

  • <u>0.40 L</u>

Explanation:

Boyle's law for gases states that, at constant temperature, the volume and pressure of a fixed amount of gas are inversely related.

Mathematically, that is:

  • PV = constant

  • P₁V₁ = P₂V₂

Here, you have:

  • V₁ = 2.4 L
  • P₁ = 14.1 Kpa
  • P₂ = 84.6 KPa
  • V₂ = ?

Then, you can solve for V₂:

  • V₂ = P₁V₁ / P₂

Substitute and compute:

  • V₂ = 14.1 KPa × 2.4L / 84.6 KPa = 0.40 L ← answer
3 0
3 years ago
For which of the following reactions is S° &gt; 0. Choose all that apply. N2(g) + 3H2(g) 2NH3(g) 2C2H6(g) + 7O2(g) 4CO2(g) + 6H2
Lostsunrise [7]

Answer: 2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

NH_4I(s)\rightarrow NH_3(g)+HI(g)

2H_2O(g)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)

Explanation:

Entropy is the measure of randomness or disorder of a system.

A system has positive value of entropy if the disorder increases and a system has negative value of entropy if the disorder decreases.

1. N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

As 4 moles of gaseous reactants are changing to 2 moles of gaseous products,  the randomness is decreasing and the entropy is negative

2. 2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

As 9 moles of gaseous reactants are changing to 10 moles of gaseous products,  the randomness is increasing and the entropy is positive.

3. NH_4I(s)\rightarrow NH_3(g)+HI(g)

As 1 mole of solid reactants is changing to 2 moles of gaseous products, the randomness is increasing and the entropy is positive.

4. 2H_2O(g)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)

As 4 moles of gaseous reactants is changing to 5 moles of gaseous products, the randomness is increasing and the entropy is positive

5. 2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(l)

As 4 moles of gaseous reactants is changing to 1 moles of gaseous products, the randomness is decreasing and the entropy is negative.

5 0
3 years ago
This is my almost last question plsss help
Morgarella [4.7K]
The third one is correct, not sure abt another one
7 0
2 years ago
Read 2 more answers
The mass of cupric sulfate needed to make .5 liters of a .5M solution is
dalvyx [7]

Answer:

C

Explanation:

3 0
3 years ago
Which substance can not be broken down by a
Tomtit [17]

Answer:  (3) silicon

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Silicon (Si)

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: ethane (C_2H_6), propanone (CH_3COCH_3) and water (H_2O)

7 0
2 years ago
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