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Stels [109]
4 years ago
12

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:

Chemistry
1 answer:
MAVERICK [17]4 years ago
8 0

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

[Ar]3d^1

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

[Ar]3d^6

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

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Answer:

Explanation:

The density of pure lead is 10.49g/cm³

Given parameters:

Volume of water displaced by the crown = 238.1ml

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Solution

We would simply find the density of the discovered crown and compare with that of the standardized density of lead.

Density is an intensive property of matter and it is the same for any form of matter. It is amount of substance per unit volume:

               Density = \frac{mass}{volume}

We need to convert the given parameters to standard unit,

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Also,

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Density = \frac{2500}{238.1} = 10.49g/cm³

The crown is made of silver because the density matches with that of pure silver.

                       

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