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Stels [109]
3 years ago
12

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:

Chemistry
1 answer:
MAVERICK [17]3 years ago
8 0

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

[Ar]3d^1

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

[Ar]3d^6

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

[Kr]4d^{10}

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

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Mole of Na ion to be prepared = Molarity x volume

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If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:

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Hence, mass of Na3PO4 = 0.1692 x molar mass

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