Electrochemical cells can be used to measure ionic concentrations. A cell is set up with a pair of Zn electrodes, each immersed
1 answer:
Answer:
the concentration of the solution is 0.00906 M
Explanation:
Given the data in the question;
we know that from Nernst Equation;
E = E⁰ - ((0.0592/n) logQ)
now, E₀ for concentration cell is 0
n for this redox is 2
concentration of the unknown solution is x
so we substitute
0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))
0.045 = -0.0296log( x/0.300 )
divide both side by 0.0296
1.52 = -log( x/0.300 )
x/0.300 =
x/0.300 = 0.0301995
we cross multiply
x = 0.300 × 0.0301995
x = 0.00906 M
Therefore, the concentration of the solution is 0.00906 M
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Ba → Ba⁺² + 2 e⁻
And Chlorine belongs to Group VII elements (Halogens), it has seven valence electrons in 3rd shell, Hence it is capable of accepting one electron and adopting -1 charge as,
Cl + e⁻ → Cl⁻
Now, for the formation of Barium Chloride we need 2 chloride ions and one Barium cation, as two -1 and one +2 charge can add to form a neutral molecule. Hence,
Ba⁺² + 2 Cl⁻ → BaCl₂
Ba → Ba⁺² + 2 e⁻
And Chlorine belongs to Group VII elements (Halogens), it has seven valence electrons in 3rd shell, Hence it is capable of accepting one electron and adopting -1 charge as,
Cl + e⁻ → Cl⁻
Now, for the formation of Barium Chloride we need 2 chloride ions and one Barium cation, as two -1 and one +2 charge can add to form a neutral molecule. Hence,
Ba⁺² + 2 Cl⁻ → BaCl₂