In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide.
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂ - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present
so if 3 mol are present in 1000 ml
then volume for 0.038 mol = 1000/3 * 0.038
= 12.67 ml
Answer:
Reproductive cells contain only four gene copy.
Explanation:
The action is interaction
Answer:
2.123x10⁻⁴ M (mol/L)
Explanation:
First, we are considering the molar mass for each element, a data we obtain from the periodic table:
Ca= 40
S= 32
O= 16
Then, for CaSO₄, the molecular mass is 136 g per mol
As we dissolve 0.00101 g of this salt, we are going to convert this mass in moles units:
1 mol CaSO₄=136 g → 0.0101 g=7.43x10⁻⁵ mol
We finally obtain the concentration for the 350 ml, having in mind that it should be in mol/L:
350ml=7.43x10⁻⁵ mol
1000ml (1L)=2.123x10⁻⁴ M , where M=mol/L
In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:
PV = nRT, where n is the number of moles. We also know that:
n = m / Mr, where m is mass and Mr is molecular weight
Thus,
Mr = (mRT)/(PV)
Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.
Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)
Mr = 21,828 g/mol
Thus, the Mr of the protein is 2.18 x 10⁴ g/mol