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3 years ago

What is the advantage of using inert gasses in a process?

Chemistry

1 answer:

omeli [17]3 years ago

5 0

Explanation:

Because of non-reactive properties of the inert gases, these gases are useful to prevent the undesirable chemical reactions to happen.

They provide a non-explosive environment. They are also cheap and economical.

Food is packed in the inert gas to prevent rancidity. This also prevents bacteria from growing.

The gases prevents the chemical oxidation by the oxygen in the normal air.

Helium is used in oxygen cylinders and also as a coolant in gas cooled reactors.

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Write the balanced net ionic equation for the reaction that occur in the following case. Cr2(SO4)3(aq)+(NH4)2CO3(aq)→

solmaris [256]

Cr2(SO4)3(aq) + 3(NH4)2CO3(aq) → 3(NH4)2SO4(aq) + Cr2(CO3)3(s)

<span>Ionic: 2Cr+3 + 3SO4^-2 + 6NH4+ + 3CO3^-2 ----> 6NH4+ + 3SO4^-2 + Cr2(CO3)3 (spectator ions are NH4+, SO4^-2) </span>

<span>Net Ionic: 2Cr^+3(aq) + 3CO3^-2(aq) -------> Cr2(CO3)3(s) </span>

6 0

3 years ago

Read 2 more answers

If you place a glass rod over a burning candle, the glass turns

gladu [14]

A. the wax is a both; 1. physical change-solid to liquid.
2. chemical change- burned to CO2 + H20 + heat + carbon as seen as black on the rod
b. the wick is neither; the wick does not change, just provides conduit for wax to flame
c. the glass rod is physical change; the carbon is only deported
HOPE THIS HELPS, IVE ALSO LEARNING BEEN LEARNING THIS RECENTLY

8 0

2 years ago

Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given

tekilochka [14]

Answer:

a) = 0.704%

b) = 1.30%

c) = 2.60%

Explanation:

Given that:

$K_a$ = $1.34*10^{-5$

For Part A; where Concentration of A = 0.270 M

Percentage Ionization(∝) $\alpha = \sqrt{\frac{K_a}{C} }$

$\alpha = \sqrt{\frac{1.34*10^{-5}}{0.270} }$

$\alpha = \sqrt{4.9629*10^{-5}}$

$\alpha = 7.044*10^{-3$

percentage% (∝) = $7.044*10^{-3}*100$

= 0.704%

For Part B; where Concentration of B = $7.84*10^{-2$ M

$\alpha = \sqrt{\frac{1.34*10^{-5}}{7.84*10^{-2}} }$

$\alpha = \sqrt{1.709*10^{-4} }$

$\alpha = 0.0130\\$

percentage% (∝) = 0.0130 × 100%

= 1.30%

For Part C; where Concentration of C= $1.92*10^{-2} M$

$\alpha = \sqrt{\frac{1.34*10^{-5}}{1.97*10^{-2}} }$

$\alpha = \sqrt{6.802*10^{-4}}$

$\alpha =0.02608$

percentage% (∝) = 0.02608 × 100%

= 2.60%

7 0

3 years ago

Creating nuclear energy produces large amounts of radioactive waste.

Montano1993 [528]

Ummmm this one is hard but i guess it would be t?????

7 0

2 years ago

How does the mass of an electron compare to the mass of a proton and a

tensa zangetsu [6.8K]

Answer:

C. The mass of an electron is much less than the mass of a proton or

a neutron.

Explanation:

When we compare the mass of an electron to that of proton or neutron, the mass of an electron is much less than the mass of a proton or a neutron.

Electrons are negatively charged particles in an atom

Protons are positively charged particles

Neutrons do not carry any charges.

The relative mass of an electron compared to that of a proton is $\frac{1}{1840}$
This is a very small value
Electrons generally have mass of 9.11 x 10⁻³¹kg
Protons weigh 1.67 x 10⁻²⁷kg

Neutrons weigh 1.68 x 10⁻²⁷kg

We can see that electrons have very small mass and this is why when calculating the mass of an atom, we use the sum of the number of protons and neutrons.

6 0

3 years ago