Answer: True the dilution formula is a balanced of mole of the solute..
Explanation:
M1V1 = M2V2
When M1= 1.2M, M2= 0.25M V2= 1.4L and V1= ?
Then V1= 0.25*1.4/1.2
= 0.29
This indicate that 0.29L of the 1.2M NH4Cl will be dilluted to 0.25M in 1.4L of the solution....
The mole number of the solute remain constant
MgCl2 would be magnesium chloride.
1. %yield = actual yield / theoretical yield x 100
= 3 g / 4. 46 g x 100
= 62.11 % percent yield
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