Answer:
Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃
The coefficients are: 1, 1, 1, 2
Explanation:
Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃
The above equation can be balance as follow:
Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃
There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before NaNO₃ as shown below:
Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃
Now the equation is balanced.
The coefficients are: 1, 1, 1, 2
Answer:
68.18%
Explanation:
The question asking for the percentage of sugar present in milk bar chocolate. To find the percentage of a certain molecule, you have to divide the mass of the molecule with the total mass of the product. The calculation will be:
sugar percentage = sugar weight / milk bar chocolate weight * 100%
sugar percentage = 7.5g / 11g * 100%= 68.18%
Answer:2 AL + FEN2 = 2 ALN + FE
Explanation: AL might be an improperly capitalized: Al. One of your compounds is AL (A and L). Did you mean Al (aluminum)?
FEN2 might be an improperly capitalized: FeN2. ALN might be an improperly capitalized: AlN
FE might be an improperly capitalized: Fe
we need the three measurements to be able to asses significant figures.
Answer:
A. Water with high salinity has low dissolved oxygen.
is your answer :)
Explanation:
