Mmm tricky.
Since the velocity is constant, I'm going to assume there is no acceleration in any direction. This means there is no net force in the I or J forection!
Since there are 2 forces, both must be equal and opposite in direction to perfectly cancel each other out.
So the opposite of F1 is (-2N)I + (6N)J!
Answer:
volume of the bubble just before it reaches the surface is 5.71 cm³
Explanation:
given data
depth h = 36 m
volume v2 = 1.22 cm³ = 1.22 ×
m³
temperature bottom t2 = 5.9°C = 278.9 K
temperature top t1 = 16.0°C = 289 K
to find out
what is the volume of the bubble just before it reaches the surface
solution
we know at top atmospheric pressure is about P1 =
Pa
so pressure at bottom P2 = pressure at top + ρ×g×h
here ρ is density and h is height and g is 9.8 m/s²
so
pressure at bottom P2 =
+ 1000 × 9.8 ×36
pressure at bottom P2 =4.52 ×
Pa
so from gas law

here p is pressure and v is volume and t is temperature
so put here value and find v1

V1 = 5.71 cm³
volume of the bubble just before it reaches the surface is 5.71 cm³
It would move slower/ faster by changing the mass, which would effect the weight and speed.