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Oksanka [162]
3 years ago
6

Logan can paint a room in 12 hours. Marcus can paint the same room in 16 hours. How long does it take for both Logan and Marcus

to paint the room if they are working together?
Mathematics
1 answer:
Anettt [7]3 years ago
8 0
Hello,

The answer should be "4".

Reason:

Since Logan takes 12 hours and Marcus takes 16 i just subtract 16 and 12.

16-14=4

=4 hours

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
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Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

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  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

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