When the capacitor is connected to the voltage, a charge Q is stored on its plates. Calling 
the capacitance of the capacitor in air, the charge Q, the capacitance and the voltage (
) are related by
(1)
when the source is disconnected the charge Q remains on the capacitor.
When the space between the plates is filled with mica, the capacitance of the capacitor increases by a factor 5.4 (the permittivity of the mica compared to that of the air):
this is the new capacitance. Since the charge Q on the plates remains the same, by using eq. (1) we can find the new voltage across the capacitor:
And since 
, substituting into the previous equation, we find:
Hello!
Remember that impulse is equivalent to:
Impulse = force (N) × time (s)
Plug in the given force and time:
Impulse = 25 × 32
Impulse = 800 Ns
Answer:
The square of orbital period is proportional to the cube of the semi-major axis.
Explanation:
I just took the quick check
The force exerted by the person is 600 N because to find the original force you would add back 100 from friction
Answer:
33% or 50% I hope that helped
