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3 years ago

What is the total number of moles present in a 526.0-gram sample of NaNCO3(s)?

Chemistry

1 answer:

dedylja [7]3 years ago

3 0

Answer:

5.42 mol

Explanation:

To find moles, divide the given mass by the compounds molar mass. To find the molar mass of the compound, add of the masses of each individual component:

Molar mass of NaNCO3 = Na + N + C + (O x 3)

Molar mass of NaNCO3 = 23 + 14 + 12 + (16 x 3)

Molar mass of NaNCO3 = 97 g/mol

Moles = mass / molar mass

Moles = 526 g / 97 g/mol

Moles = 5.42 mol

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How many moles of ammonia can be formed from 4.0 mol H2

Bess [88]

Answer: 1. 2.7 moles of ammonia are formed

2. 12.0 moles of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

$N_2+3H_2\rightarrow 2NH_3$

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form = $\frac{2}{3}\times 4.0=2.7moles$ of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by = $\frac{3}{2}\times 8.0=12.0moles$ of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with = $\frac{1}{3}\times 6.0=2.0moles$ of nitrogen

3 0

2 years ago

A device that does work with only one movement and changes the size or direction of a force is a(n) ____.

worty [1.4K]

Answer:

A device that does work with only one movement and changes the size or direction of a force is a simple machine.

Explanation:

For applying force, any used basic mechanical devices are simple machines.
Simple machine changes the direction as well as the amplitude of the applied force i.e. we can increase or decrease the magnitude of the force.
A simple machine is the most basic mechanism to use the force as we need in big mechanical machines.
Some of the examples of simple machines are inclined plane, lever, wedge, wheel and axle, pulley, and screw.

6 0

2 years ago

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will

stiks02 [169]

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

6 0

3 years ago

Is anybody good in Chemistry that can help me with this?

sesenic [268]

Answer:

just replace the 9 mole with 3.68 g of Al .

I think it will help you.