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Rzqust [24]
3 years ago
8

What is the total number of moles present in a 526.0-gram sample of NaNCO3(s)?

Chemistry
1 answer:
dedylja [7]3 years ago
3 0

Answer:

5.42 mol

Explanation:

To find moles, divide the given mass by the compounds molar mass. To find the molar mass of the compound, add of the masses of each individual component:

Molar mass of NaNCO3 = Na + N + C + (O x 3)

Molar mass of NaNCO3 = 23 + 14 + 12 + (16 x 3)

Molar mass of NaNCO3 = 97 g/mol

Moles = mass / molar mass

Moles = 526 g / 97 g/mol

Moles = 5.42 mol

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3 years ago
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<h3>Word matching</h3>

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2 years ago
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