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3 years ago

A liquid that occupies a volume of 2.68 l has a mass of 2.40 kg what is the density of the liquid in kgl/?

1 answer:

5 0

As we know the formula for density is .. Density = Mass/ Volume

So therefore putting in the values we get..

D=2.40/2.68

D= 0.89 kg/l

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_____ is the breakdown of rock by natural forces and chemical changes. A. Erosion B. Weathering C. Crystallization D. Metamorphi

sp2606 [1]

Answer:

Weathering is the breakdown of rock by natural forces and chemical changes

Explanation:

The air and water (rain) are natural forces that breaks down rocks

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3 years ago

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HELPPP ILL MARK BRAINLIEST!!!! PLS ITS DUE RIGHT NOW!

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Q. How many molecules of H2O can be produced from reactants in container below?

A. 3 molecule of molecules H2O will be produced from reactants in container.

Explanation:

There are seven molecules of H2 and three molecule of O2 are there in the container Q, 6 molecules of H2 will react with 3 molecules of O2 to produce 3 molecules of H2O. One molecule of Hydrogen will not take part in reaction and will be present in container Q after then reaction, and the mass in overall reaction is conserved!

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2 years ago

Actual conjugate acid of acetamide

viva [34]

CH3-C-NH2

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3 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m

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Answer: The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For butane:

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol$

For oxygen gas:

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol$

The chemical equation for the reaction of butane and oxygen gas follows:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = $\frac{13}{2}\times 0.224=1.456mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = $\frac{10}{2}\times 0.224=1.12moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

$1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g$

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

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3 years ago

The source of bitterness in dark chocolate is the compound theobromine, an alkaloid present in cocoa beans. In a sample of dark

spin [16.1K]

Answer: 193 mg of theobromine are present in the sample.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}=\frac{6.45\times 10^{20}}{6.023\times 10^{23}}=1.07\times 10^{-3}moles$

1 mole of theobromine $(C_7H_8N_4O_2)$ weigh = 180 g

$1.07\times 10^{-3}moles$ of theobromine $(C_7H_8N_4O_2)$ weigh = $\frac{180}{1}\times 1.07\times 10^{-3}=0.193g=193mg$ (1g=1000mg)

193 mg of theobromine are present in the sample.

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3 years ago